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Home » P4O6 reacts with water according to equation P4O6 + 6H2O → 4H3PO3. Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.
P4O6 reacts with water according to equation P4O6 + 6H2O → 4H3PO3. Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.
CBSE | Chemistry | Class 12 | Exercise 1 | NCERT Exemplar | The P-Block Elements
P4O6 reacts with water according to equation P4O6 + 6H2O → 4H3PO3. Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.

Calculation:

P4O6 + 6H2O → 4H3PO3

4H3PO3 + 8NaOH → Na2HPO3 + 8H20

P4O6 + 8NaOH → 4Na2HPO3 + 2H2O

Moles of P4O6 = 1.1/220 = 0.5

Acid formed by one mole of P4o6 requires = 8 mol

Acid formed by 0.005 mol of NaOH is present in 100mL solution

0.04 of NaOH is present in solution = 1000/0.1 *0.04 = 400mL

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