Show that for a particle executing SHM, velocity, and displacement have a phase difference of π/2.
Show that for a particle executing SHM, velocity, and displacement have a phase difference of π/2.

Answer:

We know that the equation for the displacement of SHM is

x = a cos ꞷt

where velocity can be determined as:

v = dx/dt = -aꞷ sin ꞷt

Here, the phase displacement is

ϕ1 = ꞷt

And the phase velocity,

ϕ2 = π/2 + ꞷt

Therefore, we can easily determine the difference in phase of displacement as follows:

= ϕ2 – ϕ1

= π/2