Noon Academy
contexto.140
2 years ago
Solution
Projection of
on
is nothing but
![\[\begin{array}{l} \vec{a}=\hat{\imath}+\hat{\jmath}+\not k \\ \vec{b}=\hat{\jmath} \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-db4c6e9123d1b3894a3c58e4835cc248_l3.png "Rendered by QuickLaTeX.com")
![\[\begin{array}{l} \mathrm{I} \vec{a} \mathrm{I}=\sqrt{3} \\ \mathrm{I} \vec{b} \mathrm{I}=1 \\ \vec{a} \cdot \vec{b}=\mathrm{I} \vec{a} \mathrm{I} \mathrm{I} \vec{b} \mathrm{I} \cos \theta=1 \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6be6bcd3c724e549521c0f00b621c805_l3.png "Rendered by QuickLaTeX.com")
![\[\text { Write the projection of the vector }(\hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}) \text { along the vector } \hat{\mathrm{j}} \text {. }\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a278fc4cab1975e27ab7b277eb2349fb_l3.png "Rendered by QuickLaTeX.com")
