The electron in the hydrogen atom is moving with a speed of $2 \times 10^{6} \mathrm{~m} / \mathrm{s}$ in an orbit of radius $0.5 \AA$. The magnetic moment of the revolving electron isA)$15 \times 10^{-24} \mathrm{Am}^{2}$B)$11 \times 10^{-24} \mathrm{Am}^{2}$C)$6 \times 10^{-24} \mathrm{Am}^{2}$D)$8 \times 10^{-24} \mathrm{Am}^{2}$

Home » The electron in the hydrogen atom is moving with a speed of in an orbit of radius . The magnetic moment of the revolving electron isA)B)C)D)

The electron in the hydrogen atom is moving with a speed of $2 \times 10^{6} \mathrm{~m} / \mathrm{s}$ in an orbit of radius $0.5 \AA$ . The magnetic moment of the revolving electron is
A) $15 \times 10^{-24} \mathrm{Am}^{2}$
B) $11 \times 10^{-24} \mathrm{Am}^{2}$
C) $6 \times 10^{-24} \mathrm{Am}^{2}$
D) $8 \times 10^{-24} \mathrm{Am}^{2}$

Physics

The electron in the hydrogen atom is moving with a speed of $2 \times 10^{6} \mathrm{~m} / \mathrm{s}$ in an orbit of radius $0.5 \AA$ . The magnetic moment of the revolving electron is
A) $15 \times 10^{-24} \mathrm{Am}^{2}$
B) $11 \times 10^{-24} \mathrm{Am}^{2}$
C) $6 \times 10^{-24} \mathrm{Am}^{2}$
D) $8 \times 10^{-24} \mathrm{Am}^{2}$

Correct option is D.

$\text { Magnetic moment, } \mathrm{m}_{0}=\frac{\text { evr }}{2}$

$=\frac{1.6 \times 10^{-19} \times 2\times 10^{6} \times 0.5 \times 10^{-10}}{2}=8 \times 10^{-24} \mathrm{Am}^{2}$

i

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