The equation of simple harmonic wave is given by y=6 \sin 2 \pi(2 t-0.1 x), where x and y are in m m and t is in seconds . The phase difference between two particles 2 \mathrm{~mm} apart at any instant is
A 18^{0}
B 36^{\circ}
C 54^{0}
D 72^{0}
The equation of simple harmonic wave is given by y=6 \sin 2 \pi(2 t-0.1 x), where x and y are in m m and t is in seconds . The phase difference between two particles 2 \mathrm{~mm} apart at any instant is
A 18^{0}
B 36^{\circ}
C 54^{0}
D 72^{0}

Correct option is D 72^{\circ}
Given equation can be written as y=6 \sin (4 \pi t-0.2 \pi x)
\therefore Phase \phi=-0.2 \pi x
\Rightarrow \phi_{1}=-0.2 \pi \mathrm{x}_{1} and \phi_{2}=-0.2 \pi \times 2
\therefore Phase difference \Delta \phi=\left|\phi_{2}-\phi_{1}\right|=\left|-0.2 \pi\left(\mathrm{x}_{2}-\mathrm{x}_{1}\right)\right|
given \left(x_{2}-x_{1}\right)=2 \mathrm{~mm} substituting in above equation we get \Delta \phi=0.2 \times 180^{0} \times 2=72^{0}