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Home » The fundamental frequency of a string stretched with a weight ‘M’ kg is ‘n’ , hertz. Keeping the vibrating length constant, the weight required to produce its octave is
The fundamental frequency of a string stretched with a weight ‘M’ kg is ‘n’ , hertz. Keeping the vibrating length constant, the weight required to produce its octave is
MHTCET | Physics
The fundamental frequency of a string stretched with a weight ‘M’ kg is ‘n’ , hertz. Keeping the vibrating length constant, the weight required to produce its octave is

1. M

2. 8 M

3. 2 M

4. 4 M

Solution: 4M

Octave means that the frequency is in the ratio : n’:n = 2:1

We know that the frequency is directly proportional to the tension. It is given as follows:

n\,\alpha \,\sqrt{T}

\therefore \frac{n'}{n}=\frac{\sqrt{T'}}{\sqrt{T}}=2

\Rightarrow T'=4T

Gievn:\,T=M

\therefore T'=4M

i

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