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Home » The gravitational force between an H-atom and another particle of mass m will be given by Newton’s law: , where r is in km and(a) M = mproton + m electron(b) M = mproton melectron (c) M is not related to the mass of the hydrogen atom(d) M = mproton +melectron magnitude of the potential energy of electron in the -atom)
The gravitational force between an H-atom and another particle of mass m will be given by Newton’s law: F=GMm/r^{2}, where r is in km and
(a) M = mproton + m electron
(b) M = mproton + melectron -B / c^{2}(B=13.6 \mathrm{eV})
(c) M is not related to the mass of the hydrogen atom
(d) M = mproton +melectron |\mathrm{V}| / \mathrm{c}^{2}-(|\mathrm{V}|= magnitude of the potential energy of electron in the \mathrm{H}-atom)
CBSE | Class 12 | ncert exemplar | Nuclei | Physics
The gravitational force between an H-atom and another particle of mass m will be given by Newton’s law: F=GMm/r^{2}, where r is in km and
(a) M = mproton + m electron
(b) M = mproton + melectron -B / c^{2}(B=13.6 \mathrm{eV})
(c) M is not related to the mass of the hydrogen atom
(d) M = mproton +melectron |\mathrm{V}| / \mathrm{c}^{2}-(|\mathrm{V}|= magnitude of the potential energy of electron in the \mathrm{H}-atom)

The correct option is:

(b) M = mproton + melectron -B / c^{2}(B=13.6 \mathrm{eV})

i

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