The horizontal range of a projectile fired at an angle of 15o is 50 m. If it is fired with the same speed at an angle of 45 degrees, its range will be a) 60 m b) 71 m c) 100 m d) 141 m
The horizontal range of a projectile fired at an angle of 15o is 50 m. If it is fired with the same speed at an angle of 45 degrees, its range will be a) 60 m b) 71 m c) 100 m d) 141 m

Answer:

The correct answer is c) 100 m

Given:

The horizontal range of a projectile that is fixed at an angle to the horizontal plane =15^{\circ}
Range =50 m
In the first case range =50= u ^{2} / g \left(\sin 2 \times 15^{\circ}\right)
50=\frac{2}{2 g }
\frac{ u ^{2}}{ g }=100
In 2nd case range =\frac{ u ^{2}}{ g \left(\sin 2 \times 45^{\circ}\right)}

As we know  \sin 90^{\circ}=1\right)

=\frac{100}{1}\left=100 m$