Class intervals | 0-8 | 8-16 | 16-24 | 24-32 | 32-40 | 40-48 |
Frequency | 5 | 3 | 10 | P | 4 | 2 |
Solution:
Class mark, xi = (upper class limit + lower class limit)/2
Class intervals | Frequency fi | Class mark xi | fixi |
0-8 | 5 | 4 | 20 |
8-16 | 3 | 12 | 36 |
16-24 | 10 | 20 | 200 |
24-32 | P | 28 | 28P |
32-40 | 4 | 36 | 144 |
40-48 | 2 | 44 | 88 |
Total | Ʃfi = 24+P | Ʃfixi = 488+28P |
Given mean = 23.4
Mean = Ʃfixi/ Ʃfi
23.4 = (488+28P)/(24+P)
23.4×(24+P) = 488+28P
561.6+23.4P = 488+28P
561.6-488 = 28P -23.4P
73.6 = 4.6 P
P = 73.6/4.6 = 16
Hence the value of P is 16.