The mean of the following distribution is 23.4. Find the value of p.
The mean of the following distribution is 23.4. Find the value of p.
Class intervals 0-8 8-16 16-24 24-32 32-40 40-48
Frequency 5 3 10 P 4 2

Solution:

Class mark, xi = (upper class limit + lower class limit)/2

Class intervals Frequency fi Class mark xi fixi
0-8 5 4 20
8-16 3 12 36
16-24 10 20 200
24-32 P 28 28P
32-40 4 36 144
40-48 2 44 88
Total Ʃfi = 24+P Ʃfixi = 488+28P

Given mean = 23.4

Mean = Ʃfixi/ Ʃfi

23.4 = (488+28P)/(24+P)

23.4×(24+P) = 488+28P

561.6+23.4P = 488+28P

561.6-488 = 28P -23.4P

73.6 = 4.6 P

P = 73.6/4.6 = 16

Hence the value of P is 16.