Class intervals | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 |
Frequency | 17 | P | 32 | q | 19 |
Solution:
Class mark, xi = (upper class limit + lower class limit)/2
Class intervals | Frequency fi | Class mark xi | fixi |
0-20 | 17 | 10 | 170 |
20-40 | P | 30 | 30P |
40-60 | 32 | 50 | 1600 |
60-80 | q | 70 | 70q |
80-100 | 19 | 90 | 1710 |
Total | Ʃ fi = 68+P+q | Ʃfixi = 3480+30P+70q |
Given sum of all frequencies, Ʃ fi = 120
68+P+q = 120
P+q = 120-68 = 52
P+q = 52
P = 52-q …(i)
Given mean = 50
Mean = Ʃfixi / Ʃ fi
50 = (3480+30P+70q)/120
50×120 = 3480+30P+70q
6000 = 3480+30P+70q
6000- 3480 = 30P+70q
2520 = 30P+70q
252 = 3P+7q …(ii)
Substitute (i) in (ii)
252 = 3(52-q)+7q
252 = 156-3q+7q
252-156 = 4q
4q = 96
q = 96/4 = 24
P = 52-24 = 28
Hence the value of P and q is 28 and 24 respectively.