Class intervals | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 |
Frequency | 7 | P | 12 | q | 8 | 5 |
Solution:
Class mark, xi = (upper class limit + lower class limit)/2
Class intervals | Frequency fi | Class mark xi | fixi |
0-20 | 7 | 10 | 70 |
20-40 | P | 30 | 30P |
40-60 | 12 | 50 | 600 |
60-80 | q | 70 | 70q |
80-100 | 8 | 90 | 720 |
100-120 | 5 | 110 | 550 |
Total | Ʃ fi = 32+P+q | Ʃfixi = 1940+30P+70q |
Given sum of all frequencies, Ʃ fi = 50
32+P+q = 50
P+q = 50-32= 18
P+q = 18
P = 18-q …(i)
Given mean = 57.6
Mean = Ʃfixi / Ʃ fi
57.6 = (1940+30P+70q)/50
57.6 ×50 = 1940+30P+70q
2880= 1940+30P+70q
2880- 1940 = 30P+70q
940 = 30P+70q
94 = 3P+7q …(ii)
Substitute (i) in (ii)
94 = 3(18-q)+7q
94 = 54-3q+7q
94-54= 4q
40 = 4q
q = 40/4 = 10
P = 18-10 = 8
Hence the value of P and q is 8 and 10 respectively.