(h = 6.6 × 10–34 J s)
(1) 1018 (2) 1017
(3) 1016 (4) 1015
Solution: Answer (3)
The power of a source is given by the expression:
(h = 6.6 × 10–34 J s)
(1) 1018 (2) 1017
(3) 1016 (4) 1015
Solution: Answer (3)
The power of a source is given by the expression: