The probability of obtaining an even prime number on each die, when a pair of dice is rolled is A. 0 B. $1 / 3$ c. $1 / 12$ D. $1 / 36$

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The probability of obtaining an even prime number on each die, when a pair of dice is rolled is
A. 0
B. $1 / 3$
c. $1 / 12$
D. $1 / 36$

The probability of obtaining an even prime number on each die, when a pair of dice is rolled is
A. 0
B. $1 / 3$
c. $1 / 12$
D. $1 / 36$

Solution:

Answer: D. $1 / 36$

Explanation: Given A pair of dice is rolled.

Hence the number of outcomes $=36$

The chance of getting an even prime number on each die is represented by the mathematical constant $P(E)$ .

As far as we can tell, the only even prime number is two.

So, $\mathrm{E}={2,2}$

$\Rightarrow P \in=1 / 36$

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