The roots of the equation $2 x^{2}-6 x+7=0$ are(a) real, unequal and rational(b) real, unequal and irrational(c) real and equal(d) imaginary

Home » The roots of the equation are(a) real, unequal and rational(b) real, unequal and irrational(c) real and equal(d) imaginary

The roots of the equation $2 x^{2}-6 x+7=0$ are
(a) real, unequal and rational
(b) real, unequal and irrational
(c) real and equal
(d) imaginary

The roots of the equation $2 x^{2}-6 x+7=0$ are
(a) real, unequal and rational
(b) real, unequal and irrational
(c) real and equal
(d) imaginary

Answer is (d) imaginary
$\begin{array}{l} \because D=\left(b^{2}-4 a c\right) \\ =(-6)^{2}-4 \times 2 \times 7 \\ =36-56 \\ =-20<0 \end{array}$

Thus, the roots of the equation are imaginary

i

Sign up now and study all subjects for free