The sum of two digit number is 15. The number obtained by interchanging the order of digits of the given number, it exceeds the given number by 9. Find the number.
The sum of two digit number is 15. The number obtained by interchanging the order of digits of the given number, it exceeds the given number by 9. Find the number.

Let the digits at unit’s place be a and ten’s place be v, respectively. Thus, the number we need to find is 10b+a.

As per the given question, the sum of the two digit number is 15. Thus, we have;

a+b=15 ……………(i)

Upon interchanging the digit’s place, the new number will  be 10a+b.

It is also given that, the new number obtained exceeds from the original number by 9. Therefore, we can write this as;

10a+b=10b+a+9

10a+b-10b-a=9

9a-9b=9

9(a-b)=9

a-b=9/9

a-b=1………………….. (ii)

On solving equation (i) and (ii), we can find value of a and b.

Now, adding the equations (i) and (ii), we get;

(a+b)+(a-b)=15+1

a+b+a-b=16

2a=16

a=16/2

a=8

Putting the value of a in the equation (i), we get value of b

8+b=5

b=15-8

b=7

Hence, the required number is, 10\times 7+8=78