Solution:
Radius of the circle = 6 cm
and length of tangent = 8 cm
Let OP be the distance
i.e. OA = 6 cm, AP = 8 cm .
OA is the radius
OA ⊥ AP
Now In right ∆OAP,
OP2 = OA2 + AP2
(By Pythagoras axiom)
= (6)2 + (8)2
=36 + 64
= 100
= (10)2
OP = 10 cm.