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Home » Two biased dice are thrown together. For the first die     , the other scores being equally likely while for the second die,     and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.
Two biased dice are thrown together. For the first die

    \[\mathbf{P}\left( \mathbf{6} \right)\text{ }=\text{ }\mathbf{1}/\mathbf{2}\]

, the other scores being equally likely while for the second die,

    \[\mathbf{P}\left( \mathbf{1} \right)\text{ }=\text{ }\mathbf{2}/\mathbf{5}\]

and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.
CBSE | Class 12 | Exercise 1 | Maths | NCERT Exemplar | Probability
Two biased dice are thrown together. For the first die

    \[\mathbf{P}\left( \mathbf{6} \right)\text{ }=\text{ }\mathbf{1}/\mathbf{2}\]

, the other scores being equally likely while for the second die,

    \[\mathbf{P}\left( \mathbf{1} \right)\text{ }=\text{ }\mathbf{2}/\mathbf{5}\]

and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.

Therefore, the required probability distribution is

i

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