Solution:
We have, the number of possible outcomes = 6 × 6 = 36.
(i) The outcomes favourable to the event ‘the sum of the two numbers is 8’ = E = {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}
The number of outcomes favourable to E = n(E) = 5.
Thus, P(E) = n(E)/ n(S) = 5/36
(ii) There is no outcome favourable to the event E = ‘the sum of two numbers is 13’.
So, n(E) = 0
Thus, P(E) = n(E)/ n(S) = 0/36 = 0