(iii)Let E be an event of getting a sum divisible by 5.

Favourable outcomes = {(1,4),(2,3), (3,2), (4,1),(4,6), (5,5), (6,4)}

Number of favourable outcomes = 7

P(E) = 7/36

Probability of getting a sum divisible by 5 is 7/36.

(iv)Let E be an event of getting a sum of at least 11.

Favourable outcomes = {(5,6),(6,5), (6,6)}

Number of favourable outcomes = 3

P(E) = 3/36 = 1/12

Probability of getting a sum of at least 11 is 1/12.