**Answer :**

According to the question, the diameter of the first bore is

**d _{1} = 3.0 mm = 3 × 10^{-3} m**The radius of the first bore is

**r _{1 }= 3/2 = 1.5 x 10^{-3} m.**

The diameter of the second bore is

**d _{2} =6mm**

The radius of the second bore is

**r _{2 }= 6/2 = 3 x 10^{-3} mm**

The surface tension of water is

**s = 7.3 × 10 ^{-2} N /m**

The angle of contact between the bore surface and water is

**θ= 0**

And the density of water is

**ρ =1.0 × 10 ^{3} kg/m^{-3}**

Acceleration due to gravity,

**g = 9.8 m/s**

^{2}Let h1 and h2 be the corresponding heights to which water rises in the first and second tubes.

As a result, the height differences can be writte using the expression of height

**Therefore, 2.482 mm is the difference in the water levels of the two arms.**