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Home » Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii and respectively. If they carry same current i, the ratio of the magnetic fields along the two loops is, (1) (2) (3)
Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 \mathrm{~cm} and 20 \mathrm{~cm} respectively. If they carry same current i, the ratio of the magnetic fields along the two loops is, (1) 1: 2 (2) 1: 1 (3) 4: 1 (4) 2: 1
Physics | Physics
Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 \mathrm{~cm} and 20 \mathrm{~cm} respectively. If they carry same current i, the ratio of the magnetic fields along the two loops is, (1) 1: 2 (2) 1: 1 (3) 4: 1 (4) 2: 1

Answer (2)
Sol. Magnetic field inside a toroid in
\mathrm{B}=\frac{\mu_{0} \mathrm{~N} \cdot \mathbf{I}}{2 \pi \mathrm{R}}
Here, \frac{\mathrm{B}_{1}}{\overline{\mathrm{B}_{2}}}=\frac{\mathrm{N}_{1} \mathrm{R}_{2}}{\mathrm{~N}_{2} \mathbf{R}_{1}}=\frac{200}{100} \frac{20}{40}=1
So, \frac{B_{1}}{B_{2}}=1

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