Two very long straight parallel wires carry steady currents i and 2 \mathrm{i} in opposite directions. The distance between the wires is \mathrm{d}. at a certain instant of time, a point charge \mathrm{q} is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity \vec{v} is perpendicular to this plane. The magnitude of the force, due to the magnetic field acting on the charge at this instant is:
A \frac{\mu_{n} i q v}{2 \pi d}
B \frac{\mu_{n} \text { iqv }}{\pi d}
C \frac{3 \mu_{n} \mathrm{iqv}}{2 \pi \mathrm{d}}
D zero
Two very long straight parallel wires carry steady currents i and 2 \mathrm{i} in opposite directions. The distance between the wires is \mathrm{d}. at a certain instant of time, a point charge \mathrm{q} is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity \vec{v} is perpendicular to this plane. The magnitude of the force, due to the magnetic field acting on the charge at this instant is:
A \frac{\mu_{n} i q v}{2 \pi d}
B \frac{\mu_{n} \text { iqv }}{\pi d}
C \frac{3 \mu_{n} \mathrm{iqv}}{2 \pi \mathrm{d}}
D zero

Correct option is (D) zero
Magnetic field at P is perpendicu;ar to paper inward due to both the wires. Charged particle is also projected in the same direction.
So, force on the charged particle is zero as \overrightarrow{\mathrm{v}} \| \overrightarrow{\mathrm{B}} ; \quad \overrightarrow{\mathrm{F}}_{\mathrm{m}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})=0