Two vibrating tuning forks produce waves which are represented by $\mathrm{Y}_{1}=4 \sin 500 \pi \mathrm{t}$ and $\mathrm{Y}_{2}=4 \mathrm{sin}$ $506 \pi \mathrm{t}$. The number of beats produced per minute by these two waves isA. 60B. 180C. 360D. 3

Home » Two vibrating tuning forks produce waves which are represented by and . The number of beats produced per minute by these two waves isA. 60B. 180C. 360D. 3

Two vibrating tuning forks produce waves which are represented by $\mathrm{Y}_{1}=4 \sin 500 \pi \mathrm{t}$ and $\mathrm{Y}_{2}=4 \mathrm{sin}$ $506 \pi \mathrm{t}$ . The number of beats produced per minute by these two waves is
A. 60
B. 180
C. 360
D. 3

Physics

Two vibrating tuning forks produce waves which are represented by $\mathrm{Y}_{1}=4 \sin 500 \pi \mathrm{t}$ and $\mathrm{Y}_{2}=4 \mathrm{sin}$ $506 \pi \mathrm{t}$ . The number of beats produced per minute by these two waves is
A. 60
B. 180
C. 360
D. 3

Correct answer is B.

$\begin{array}{l} \mathrm{Y}_{1}=4 \sin (500 \pi \mathrm{t}) \\ \mathrm{Y}_{2}=2 \sin (506 \pi \mathrm{t}) \\ \mathrm{f}_{1}=\frac{\omega_{1}}{2 \pi}=\frac{500 \pi}{2 \pi}=250 \\ \mathrm{f}_{2}=\frac{\omega_{2}}{2 \pi}=\frac{506 \pi}{2 \pi}=253 \\ \beta=\mathrm{f}_{2}-\mathrm{f}_{1}=253-250=3 \text { beats } / \mathrm{sec} \end{array}$
So, beat per minute is $3\times60=180$

i

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