Solution:-
(i) We have to find the value of 2 sin θ – cos θ
From the question it is given that, value of θ = 35o
So, substitute the value of θ,
= 2 sin 35o – cos 35o
From the table value of sin 35o = .5736 and cos 35o = .8192
= (2 × .5736) – .8192
= 0.3280
(ii) from the question it is given that, tan θ = .2679
In the table of natural sines, look for a value (≤ .2679) which is sufficiently close to .2679.
We find the value column headed by 15o.
So we get, θ = 15o
So, substitute the value of θ,
= 2 sin 15o – cos 15o
From the table value of sin 15o = .2588 and cos 15o = .9659
= (2 × .2588) – .9659
= -0.4483