What is displacement current? Obtain an expression of displacement current for a charged capacitor. Write Ampere-Maxwell’s law.
What is displacement current? Obtain an expression of displacement current for a charged capacitor. Write Ampere-Maxwell’s law.

Current passes through the circuit while a capacitor is charging (or draining). However, no actual charge transfer occurs in the insulated region between the capacitors, which is incompatible with current flow. As a result, displacement current is the current flowing through the insulated zone as the electric flux changes.
For a charged capacitor, electric field between the plates is given by:

    \[\begin{array}{l} \mathrm{E}=\frac{\mathrm{Q}}{\varepsilon_{0} \mathrm{~A}} \\ \mathrm{Q}=\varepsilon_{0} \phi_{\mathrm{E}} \end{array}\]

Displacement current is given by:

    \[\mathrm{i}_{\mathrm{d}}=\frac{\mathrm{dQ}}{\mathrm{dt}}=\varepsilon_{\mathrm{0}} \frac{\mathrm{d} \phi \mathrm{E}}{\mathrm{dt}}\]

According to Maxwell’s Ampere circuital Law, the line integral of magnetic field along a closed path is equal to \mu_{0} times the total current.

    \[\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dl}}=\mu_{\mathrm{o}}\left(\mathrm{i}_{\mathrm{c}}+\mathrm{i}_{\mathrm{d}}\right)\]

where \mathrm{i}_{\mathrm{c}} : Conduction current
\mathrm{i}_{\mathrm{d}} : Displacement current

    \[\oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dl}}=\mu_{0}\left(\mathrm{i}_{\mathrm{c}}+\varepsilon_{0} \frac{\mathrm{d} \phi}{\mathrm{dt}}\right)\]