A. sp3d2
B. sp3d3
C. sp3d
D. dsp2
Solution: sp3d2
PCl5 is expected to have a hybridization of sp3d and a shape of trigonal bipyramidal. But in solid-state PCl5 exists in ionic form as PCl+4 and PCl−6 and thus shows sp3 and sp3d2 hybridizations, respectively. Therefore, the correct answer is sp3d2 hybridization.