Which of the following are quadratic equation in $x$?(i) $x^{2}-3 x-\sqrt{x}+4=0$(ii) $x-\frac{6}{x}=3$

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Which of the following are quadratic equation in $x$ ?
(i) $x^{2}-3 x-\sqrt{x}+4=0$
(ii) $x-\frac{6}{x}=3$

Which of the following are quadratic equation in $x$ ?
(i) $x^{2}-3 x-\sqrt{x}+4=0$
(ii) $x-\frac{6}{x}=3$

(i) $\left(x^{2}-3 x-\sqrt{x}+4\right)$ contains a term with $\sqrt{x}$ , i.e., $x^{\frac{1}{2}}$ , where $\frac{1}{2}$ is not a integer.

Therefore, it is not a quadratic polynomial.

$\therefore x^{2}-3 x-\sqrt{x}+4=0$ is not a quadratic equation.

(ii)
$\begin{array}{l} x-\frac{6}{x}=3 \\ \Rightarrow x^{2}-6=3 x \\ \Rightarrow x^{2}-3 x-6=0 \end{array}$

$\left(x^{3}-3 x-6\right)$ is not quadratic polynomial; therefore, the given equation is quadratic.

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