Which of the following is not an octahedral complex?
Which of the following is not an octahedral complex?

1.\,\,{{[Ir{{({{C}_{2}}{{O}_{4}})}_{2}}C{{l}_{2}}]}^{3-}}

2.\,\,{{[CoC{{l}_{2}}{{(en)}_{2}}]}^{+}}

3.\,\,{{\left[ Co{{(en)}_{2}}{{(N{{O}_{3}})}_{2}} \right]}^{+}}

4.\,\,\left[ Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}} \right]

Solution:  4.\,\,\left[ Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}} \right]

Because Pt(II) is a transition metal, Pt(NH3)2Cl2 is a square planar. For transition metals with a d8 electron configuration, square planar is the favoured shape.

The oxidation sate of Pt in the given complex is +2.

P{{t}^{2+}}:{{[Xe]}^{54}}4{{f}^{14}}5{{d}^{8}}

The eight electrons in the 5d-subshell pair up in four d-orbitals, followed by 4sp2-hybridization, resulting in a square planar complex.