Write first four terms of the A.P., when the first term a and the common difference d are given as follows: (i)

    \[\mathbf{a}\text{ }=\text{ }\mathbf{10},\text{ }\mathbf{d}\text{ }=\text{ }\mathbf{10}\]

(ii)

    \[\mathbf{a}\text{ }=\text{ }-\mathbf{2},\text{ }\mathbf{d}\text{ }=\text{ }\mathbf{0}\]

Write first four terms of the A.P., when the first term a and the common difference d are given as follows: (i)

    \[\mathbf{a}\text{ }=\text{ }\mathbf{10},\text{ }\mathbf{d}\text{ }=\text{ }\mathbf{10}\]

(ii)

    \[\mathbf{a}\text{ }=\text{ }-\mathbf{2},\text{ }\mathbf{d}\text{ }=\text{ }\mathbf{0}\]

From the question it is given that,

First term a =

    \[10\]

Common difference d =

    \[10\]

Then the first four terms are =

    \[10+10=20\]

    \[\begin{array}{*{35}{l}} 20\text{ }+\text{ }10\text{ }=\text{ }30  \\ 30\text{ }+\text{ }10\text{ }=\text{ }40  \\ \end{array}\]

Therefore, first four terms are

    \[10,\text{ }20,\text{ }30\text{ }and\text{ }40\]

.

(ii)

    \[\mathbf{a}\text{ }=\text{ }-\mathbf{2},\text{ }\mathbf{d}\text{ }=\text{ }\mathbf{0}\]

Solution:-

From the question it is given that,

First term a =

    \[-2\]

Common difference d =

    \[0\]

Then the first four terms are =

    \[-2\text{ }+\text{ }0\text{ }=\text{ }-2\]

    \[\begin{array}{*{35}{l}} -2\text{ }+\text{ }0\text{ }=\text{ }-2  \\ -2\text{ }+\text{ }0\text{ }=\text{ }-2  \\ \end{array}\]

Therefore, first four terms are  

    \[-2,\text{ }-2,\text{ }-2\text{ }and\text{ }-2\]

.