Solution:
Given equations are
And, 
Integrating by parts, we get
![\begin{array}{l} =\left[y \cos ^{-1} y-\sqrt{1-y^{2}}\right]_{\frac{1}{\sqrt{2}}}^{1}+\left[x \sin ^{-1} x+\sqrt{1-x^{2}}\right]_{0}^{\frac{1}{\sqrt{2}}} \\ =\left[\cos ^{-1}(1)-\frac{1}{\sqrt{2}} \cos ^{-1}\left(\frac{1}{\sqrt{2}}\right)+\sqrt{1-\frac{1}{2}}\right]+\left[\frac{1}{\sqrt{2}} \sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)+\sqrt{1-\frac{1}{2}}-1\right] \\ =\frac{-\pi}{4 \sqrt{2}}+\frac{1}{\sqrt{2}}+\frac{\pi}{4 \sqrt{2}}+\frac{1}{\sqrt{2}}-1 \\ =\frac{2}{\sqrt{2}}-1 \\ =\sqrt{2}-1 \text { sq.units } \end{array}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ee28bb312079c05131928446af378649_l3.png "Rendered by QuickLaTeX.com")
As a result, the correct answer is 
Choose the correct option: The area bounded by the 
A. 
B. 
C. 
D. 
Solution:
Given equations are
And,
Integrating by parts, we get
As a result, the correct answer is
