Find the 16th term from the end of the AP 7, 2, –3, –8, –13, …., –113

To Find : 28th term from the end of the AP.
Given: The AP is 7, 2, –3, –8, –13, …., –113
a1 = 7, a2 = 2, d = 2–7 = –5 and l = –113
Formula Used: nth term from the end = l– (n–1)d
(Where l is last term and d is common difference of given AP)
By using nth term from the end = l– (n–1)d formula
16th term from the end = (–113) – 15d → (–113)–15 × (–5) = –38
So 16th term from the end is equal to –38.