To Find : 28th term from the end of the AP.
Given: The AP is 7, 2, –3, –8, –13, …., –113
a1 = 7, a2 = 2, d = 2–7 = –5 and l = –113
Formula Used: nth term from the end = l– (n–1)d
(Where l is last term and d is common difference of given AP)
By using nth term from the end = l– (n–1)d formula
16th term from the end = (–113) – 15d → (–113)–15 × (–5) = –38
So 16th term from the end is equal to –38.
Find the 16th term from the end of the AP 7, 2, –3, –8, –13, …., –113
Find the 16th term from the end of the AP 7, 2, –3, –8, –13, …., –113