Physics

a) Consider the circuit in the figure. How much energy is absorbed by electrons from the initial state of no current to the state of drift velocity? b) Electrons give up energy at the rate of RI2 per second to the thermal energy. What time scale would one associate with energy in problem a) n = no of electron/volume = 1029/m3, length of circuit = 10 cm, cross-section = A = 1mm2

a) Current is given as I = V/R from the Ohm’s law Therefore, I = 1A But, I = ne Avd vd = I/neA When the values for the above parameters are substituted, vd = 1/1.6 × 10-4 m/s The KE = (KE of one...

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 In an experiment with a potentiometer, VB = 10V. R is adjusted to be 50 Ω. A student wanting to measure voltage E1 of a battery finds no null point possible. He then diminishes R to 10 Ω and is able to locate the null point on the last segment of the potentiometer. Find the resistance of the potentiometer wire and potential drop per unit length across the wire in the second case.

Equivalent resistance of the potentiometer = 50 Ohm + R’ Equivalent voltage across the potentiometer = 10 V Current through the main circuit I = 10/(50 Ohms +R’) Potential difference across wire of...

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A room has AC run for 5 hours a day at a voltage of 220V. The wiring of the room consists of Cu of 1 mm radius and a length of 10 m. Power consumption per day is 10 commercial units. What fraction of it goes in the joule heating in wires? What would happen if the wiring is made of aluminium of the same dimensions?

Power consumption in a day = 10 units Power consumption per hour = 2 units Power consumption = 2 units = 2 kW = 2000 J/s Power consumption in resistors, P = VI Which gives I = 9A We know that...

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Two cells of voltage 10V and 2V and internal resistances 10Ω and 5Ω respectively are connected in parallel with the positive end of the 10V battery connected to the negative pole of 2V battery. Find the effective voltage and effective resistance of the combination.

Kirchhoff’s law is applied at c, I1 = I + I2 Kirchhoff’s law is applied at efbae, 10 – IR – 10I2 = 0 10 = IR + 10I1 Kirchhoff’s law is applied at cbadc, -2-IR+5I2 = 0 2 = 5I2- RI I2 = I1 – I...

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Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1 mm. Conductor B is a hollow tube of outer diameter 2 mm and inner diameter 1 mm. Find the ratio of resistance RA to RB.

Resistance of wire R = ρ l/A Where A is the cross-sectional area of the conductor L is the length of the conductor ρ is the specific resistance RA = ρl/π(10-3 × 0.5)2 RB = ρl/ π[10-3)2 × (0.5 ×...

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The circuit in the figure shows two cells connected in opposition to each other. Cell E1 is of emf 6V and internal resistance 2Ω; the cell E2 is of emf 4V and internal resistance 8 Ω. Find the potential difference between the points A and B.

Applying Ohm’s law, equivalent emf of the two cells = 6 – 4 = 2V Equivalent resistance = 2 + 8 = 10 Ω Electric current, I = 6-4/2+8 = 0.2A When the loop is considered in the anti-clockwise...

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An infinitely long cylinder of radius R is made of an unusual exotic material with refractive index –1. The cylinder is placed between two planes whose normals are along the y-direction. The centre of the cylinder O lies along the y-axis. A narrow laser beam is directed along the y-direction from the lower plate. The laser source is at a horizontal distance x from the diameter in the y-direction. Find the range of x such that light emitted from the lower plane does not reach the upper plane.

The refractive index of the cylinder is -1 and is placed in the air of μ = 1 AB is incident at B to the cylinder such that θr will be negative θ1= θi = θr Total deviation of the outcoming ray is...

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If light passes near a massive object, the gravitational interaction causes a bending of the ray. This can be thought of as happening due to a change in the effective refractive index of the medium given by n(r) = 1 + 2 GM/rc2 where r is the distance of the point of consideration from the centre of the mass of the massive body, G is the universal gravitational constant, M the mass of the body and c the speed of light in vacuum. Considering a spherical object find the deviation of the ray from the original path as it grazes the object.

n(r) = 1 + 2GM/rc2

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The mixture a pure liquid and a solution in a long vertical column (i.e, horizontal dimensions << vertical dimensions) produces diffusion of solute particles and hence a refractive index gradient along the vertical dimension. A ray of light entering the column at right angles to the vertical deviates from its original path. Find the deviation in travelling a horizontal distance d << h, the height of the column.

Let the height of the long vertical column with transparent liquid be h and dx be the thickness The angle at which the ray AB enters is θ Let y be the new height of the liquid (θ + d θ) is the...

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A myopic adult has a far point at 0.1 m. His power of accomodation is 4 diopters. (i) What power lenses are required to see distant objects? (ii) What is his near point without glasses? (iii) What is his near point with glasses? (Take the image distance from the lens of the eye to the retina to be 2 cm.)

i) Power lenses are required to see distant objects 1/f = 1/v – 1/u 1/f = 1/10 f = -10 cm = -0.1 m P = 1/f P = 1/(-0.1) P = -10 diopter ii) When no corrective lens used Pn = Pf + Pa u = -10 cm =...

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In many experimental set-ups the source and screen are fixed at a distance say D and the lens is movable. Show that there are two positions for the lens for which an image is formed on the screen. Find the distance between these points and the ratio of the image sizes for these two points.

u = -x1 v = +(D – x1) 1/D – x1 – 1/(-x1) = 1/f u = -x2 v = +(D – x2) 1/D – x2 – 1/(-x2) = 1/f D = x1 + x2 d = x2 – x1 x1 = D – d/2 D – x1 = D + d/2 u = D/2 + d/2 v = D/2 – d/2 m1 = D – d/D + d m2/m1...

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A circular disc of radius ‘R’ is placed co-axially and horizontally inside an opaque hemispherical bowl of radius ‘a’. The far edge of the disc is just visible when viewed from the edge of the bowl. The bowl is filled with transparent liquid of refractive index µ and the near edge of the disc becomes just visible. How far below the top of the bowl is the disc placed?

        Distance at which the bowl should be placed in the disc is given as: d = μ(a2 – b2)/√(a + r)2 – μ(a – r)2

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You are given four sources of light each one providing a light of a single colour- red, blue, green, and yellow. Suppose the angle of refraction for a beam of yellow light corresponding to a particular angle of incidence at the interface of two media is 90o. Which of the following statements is correct if the source of yellow light is replaced with that of other lights without changing the angle of incidence?
a) the beam of red light would undergo total internal reflection
b) the beam of red light would bend towards normal while it gets refracted through the second medium
c) the beam of blue light would undergo total internal reflection
d) the beam of green light would bend away from the normal as it gets refracted through the second medium

Answer: c) the beam of blue light would undergo total internal reflection

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A ray of light incident at an angle θ on a refracting face of a prism emerges from the other face normally. If the angle of the prism is 5o and the prism is made of a material of refractive index 1.5, the angle of incidence is
a) 7.5o
b) 5o
c) 15o
d) 2.5o

Answer: a) 7.5o The distance between the refracting surfaces is negligible with thin prisms, thus the prism angle (A) is very small. Because A = r1 + r2, if A is tiny, both r1 and r2 will be little...

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Two cells of same emf E but internal resistance r1 and r2 are connected in series to an external resistor R. What should be the value of R so that the potential difference across the terminals of the first cell becomes zero.

Effective emf of two cells = E + E = 2E Effective resistance = R + r1 + r2 Electric current is given as I = 2E/R+r1+r2 Potential difference is given as V1 – E – Ir1 = 0 Which f=gives R = r1 –...

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Let there be n resistors R1……..Rn with Rmax = max(R1……Rn) and Rmin = min(R1…….Rn). Show that when they are connected in parallel, the resultant resistance Rp < Rmin and when they are connected in series, the resultant resistance Rs > Rmax. Interpret the result physically.

  The current is represented as I = E/R+nR when the resistors are connected in series. Current is expressed as 10I = E/(R+R/n) when the resistors are connected in parallel....

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First, a set of n equal resistors of R each are connected in series to a battery of emf E and internal resistance R. A current I is observed to flow. Then the n resistors are connected in parallel to the same battery. It is observed that the current is increased 10 times. What is ‘n’?

The current is represented as I = E/R+nR when the resistors are connected in series. Current is expressed as 10I = E/(R+R/n) when the resistors are connected in parallel. We get n = 10 by solving...

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While doing an experiment with potentiometer it was found that the deflection is one-sided and i) the deflection decreased while moving from one end A of the wire to the end B; ii) the deflection increased, while the jockey was moved towards the end B. i) Which terminal +ve or –ve of the cell E, is connected at X in case
i) and how is E1 related to E?
ii) Which terminal of the cell E1 is connected at X in case ii)?

The positive terminal of cell E1 is linked to E, and E is connected to X.  Furthermore, E1 > E ii) cell E1's negative terminal is linked to X.

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The relaxation time τ is nearly independent of applied E field whereas it changes significantly with temperature T. First fact is responsible for Ohm’s law whereas the second fact leads to a variation of ρ with temperature. Elaborate why?

Relaxation time is the time interval between two successive collisions of the electrons.It is defined asτ = mean free path/rms velocity of electrons usually, the drift velocity of the electrons is...

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Temperature dependence of resistivity ρ(T) of semiconductors, insulators, and metals is significantly based on the following factors:
a) number of charge carriers can change with temperature T
b) time interval between two successive collisions can depend on T
c) length of material can be a function of T
d) mass of carriers is a function of T

The correct answer is a) number of charge carriers can change with temperature T b) time interval between two successive collisions can depend on T

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In a meter bridge, the point D is a neutral point.
a) the meter bridge can have no other neutral point for this set of resistances
b) when the jockey contacts a point on meter wire left of D, current flows to B from the wire
c) when the jockey contacts a point on a meter wire to the right of D, current flows from B to the wire through the galvanometer
d) when R is increased, the neutral point shifts to left

The correct answer is a) the meter bridge can have no other neutral point for this set of resistances c) when the jockey contacts a point on a meter wire to the right of D, current flows from B to...

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Temperature dependence of resistivity ρ(T) of semiconductors, insulators, and metals is significantly based on the following factors:
a) number of charge carriers can change with temperature T
b) time interval between two successive collisions can depend on T
c) length of material can be a function of T
d) mass of carriers is a function of T

solution:The correct answer is a) number of charge carriers can change with temperature T b) time interval between two successive collisions can depend on T

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Consider a simple circuit in the figure.stands for a variable resistance R’.
R’ can vary from R0 to infinity. r is internal resistance of the battery,
a) potential drop across AB is nearly constant as R’ is varied
b) current through R’ is nearly a constant as R’ is varied
c) current I depends sensitively on R’
d) I ≥V/r+R always

solution: The correct answer is a) potential drop across AB is nearly constant as R’ is varied d) I ≥V/r+R always  

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Kirchhoff’s junction rule is a reflection of
a) conservation of current density vector
b) conservation of charge
c) the fact that the momentum with which a charged particle approaches a junction is unchanged as the charged particle leaves the junction
d) the fact that there is no accumulation of charges at a junction

solution: The correct answer is b) conservation of charge d) the fact that there is no accumulation of charges at a junction

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A metal rod of length 10 cm and a rectangular cross-section of 1 cm × 1/2 cm is connected to battery across opposite faces. The resistance will be
a) maximum when the battery is connected across 1 cm × 1/2 cm faces
b) maximum when the battery is connected across 10 cm × 1 cm faces
c) maximum when the battery is connected across 10 cm × 1/2 cm faces
d) same irrespective of the three faces

solution:The correct solution is a) maximum when the battery is connected across 1 cm × 1/2 cm faces

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Two cells of emf’s approximately 5V and 10V are to be accurately compared using a potentiometer of length 400 cm.
a) the battery that runs the potentiometer should have voltage of 8V
b) the battery of potentiometer can have a voltage of 15V and R adjusted so that the potential drop across the wire slightly exceeds 10V
c) the first portion of 50 cm of wire itself should have a potential drop of 10V
d) potentiometer is usually used for comparing resistances and not voltages

Solution: The correct solution is b) the potentiometer's battery can be set to 15V and R adjusted so that the potential drop across the wire is a little higher than 10V.

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A resistance R is to be measured using a meter bridge. Student chooses the standard resistance S to be 100Ω. He finds the null point at l1 = 2.9 cm . He is told to attempt to improve the accuracy. Which of the following is a useful way?
a) he should measure l1 more accurately
b) he should change S to 1000 Ω and repeat the experiment
c) he should change S to 3 Ω and repeat the experiment
d) he should give up hope of a more accurate measurement with a meter bridge

solution:The correct answer is c) he should change S to 3 Ω and repeat the experiment

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Two batteries of emf ε1 and ε2 and internal resistances r1 and r2 respectively are connected in parallel as shown in the figure.a) the equivalent emf εeq of the two cells is between ε1 and ε2 that is ε1 < εeq < ε2
b) the equivalent emf εeq is smaller than ε1
c) the εeq is given by εeq = ε1 + ε2 always
d) εeq is independent of internal resistances r1 and r2

      solution: The correct answer is a) the equivalent emf εeq of the two cells is between ε1 and ε2 that is ε1 < εeq < ε2

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Consider a current-carrying wire in the shape of a circle. Note that as the current progresses along the wire, the direction of j changes in an exact manner, while the current I remain unaffected. The agent that is essentially responsible for is
a) source of emf
b) electric field produced by charges accumulated on the surface of wire
c) the charges just behind a given segment of wire which push them just the right way by repulsion
d) the charges ahead

solution: The correct answer is b) electric field produced by charges accumulated on the surface of wire

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The figure shown a two-slit arrangement with a source which emits unpolarised light. P is a polariser with axis whose direction is not given. If I0 is the intensity of the principal maxima when no polarizer is present, calculate in the present case, the intensity of the principal maxima as well as of the first minima.

Given wave amplitude in perpendicular polarisation $ A_{\perp}=A_{\perp}^{0}(\sin (k x-\omega t)+\sin (k x-\omega t+\phi)) $ wave amplitude in parallel polarisation $ A_{\|}=A_{\|}^{0}(\sin (k...

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AC = CO = D, S1 C = S2 C = d << D A small transparent slab containing material of µ =1.5 is placed along AS2. What will be the distance from O of the principal maxima and of the first minima on either side of the principal maxima obtained in the absence of the glass slab?

According to the question, $ \begin{array}{l} \Delta x=2 d \sin \theta+(\mu-1) L \\ \sin \theta 0=-1 / 16 \end{array} $ From central maxima, $O P=-D / 16$ $ \sin \theta_{1}=\frac{\pm \lambda / 2-d /...

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The Bohr model for the H-atom relies on the Coulomb’s law of electrostatics. Coulomb’s law has not directly been verified for very short distances of the order of angstroms. Supposing Coulomb’s law between two opposite charge +q 1,-q 2 is modified to =\frac{q_{1} q_{2}}{\left(4 \pi \epsilon_{0}\right)} \frac{1}{R_{0}^{2}}\left(\frac{R_{0}}{r}\right)^{\epsilon}, r \leq R_{0} \quad Calculate in such a case, the ground state energy of an \mathrm{H}- atom, if \varepsilon

Case 1: When $\varepsilon=0.1, \mathrm{R_O}=1 \mathrm{~A}$ $\mathrm R_1=8 \times 10^{-11}$ $\mathrm{M}=0.08 \mathrm{~nm}$ Velocity at ground level is given as $\mathrm v_1=1.44 \times 10^{6}...

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The inverse square law in electrostatics is |F|=\frac{e^{2}}{\left(4 \pi \epsilon_{0}\right)} r^{2} for the force between an electron and a proton. The 1 \mathrm{r} dependence of |\mathbf{F}| can be understood in quantum theory as being due to the fact that the ‘particle’ of light (photon) is massless. If photons had a mass \mathrm{mp}, force would be modified to |F|=\frac{e^{2}}{\left(4 \pi \epsilon_{0}\right)} r^{2}\left[\frac{1}{r^{2}}+\frac{\lambda}{r}\right] \quad where \lambda=\mathrm{m} \mathrm{cp} / \hbar and h=\hbar / 2 \pi . Estimate the change in the ground state energy of an H-atom if \mathrm{mp} were 10^{-6} times the mass of an electron.

$m_{\mathrm{p}} c^{2}=10^{-6} \times$ electron mass $\times c^{2}$ $=10^{-6} \times 0.5 \mathrm{MeV}$ $\approx 10^{-6} \times 0.5 \times 1.6 \times 10^{-13}$ $\approx \mathrm{O} .8 \times 1...

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In the Auger process, an atom makes a transition to a lower state without emitting a photon. The excess energy is transferred to an outer electron which may be ejected by the atom. (This is called an Auger electron). Assuming the nucleus to be massive, calculate the kinetic energy of an \mathrm{n}=4 Auger electron emitted by Chromium by absorbing the energy from an =2 to n=1 transition.

The energy in the nth state can be calculated as, $-\operatorname{Rch} Z^{2} / n^{2}=-13.6 z^{2} / n^{2} e V$ Where $R=$ Rydberg constant and $\mathrm{Z}=24$ Energy released is given as $\left(13.6...

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Deuterium was discovered in 1932 by Harold Urey by measuring the small change in wavelength for a particular transition in 1 \mathrm{H} and 2 \mathrm{H}. This is because the wavelength of transition depends to a certain extent on the nuclear mass. If nuclear motion is taken into account then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass \mu, revolving around the nucleus at a distance equal to the electron-nucleus separation. Here \mu=\mathrm{me} \mathrm{M} /(\mathrm{me}+\mathrm{M}) where \mathrm{M} is the nuclear mass and \mathrm{me} is the electronic mass. Estimate the percentage difference in wavelength for the 1 st line of the Lyman series in 1 \mathrm{H} and 2 \mathrm{H}. (Mass of 1 \mathrm{H} nucleus is 1.6725 \times 10^{-27} \mathrm{~kg}, Mass of 2 \mathrm{H} nucleus is 3.3374 \times 10^{-27} \mathrm{~kg}, Mass of electron =9.109 \times 10^{-31} kg.)

The energy of an electron in the nth state is given by the expression, $E_ n=-\mu Z^{2} \mathrm{e}^{4} / 8 \varepsilon_ 0^{2} h^{2}\left(1 / n^{2}\right)$ For hydrogen atom we have, $\mu...

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Let E_{n}=\frac{-1}{8 \epsilon_{0}^{2}} \frac{m e^{4}}{n^{2} h^{2}} \quad be the energy of the nth level of H-atom. If all the H-atoms are in the ground state and radiation of frequency (E_2-E_1)/h falls on it
(a) it will not be absorbed at all
(b) some of the atoms will move to the first excited state
(c) all atoms will be excited to the n=2 state
(d) no atoms will make a transition to the \mathrm{n}=3 state

The correct options are: (b) some of the atoms will move to the first excited state (d) no atoms will make a transition to the $n=3$ state

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The Balmer series for the H-atom can be observed
(a) if we measure the frequencies of light emitted when an excited atom falls to the ground state
(b) if we measure the frequencies of light emitted due to transitions between excited states and the first excited state
(c) in any transition in a \mathrm{H}-atom
(d) as a sequence of frequencies with the higher frequencies getting closely packed

The correct options are: (b) if we measure the frequencies of light emitted due to transitions between excited states and the first excited state (d) as a sequence of frequencies with the higher...

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Consider aiming a beam of free electrons towards free protons. When they scatter, an electron and a proton cannot combine to produce an H-atom,
(a) because of energy conservation
(b) without simultaneously releasing energy in the form of radiation
(c) because of momentum conservation
(d) because of angular momentum conservation

The correct options are: (a) because of energy conservation (b) without simultaneously releasing energy in the form of radiation

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An ionised H-molecule consists of an electron and two protons. The protons are separated by a small distance of the order of angstrom. In the ground state,
(a) the electron would not move in circular orbits
(b) the energy would be (2) 4 times that of an \mathrm{H}-atom
(c) the electrons, the orbit would go around the protons
(d) the molecule will soon decay in a proton and an \mathrm{H}-atom

The correct options are: (a) the electron would not move in circular orbits (c) the electrons, the orbit would go around the protons

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\mathrm{O}_{2} molecule consists of two oxygen atoms. In the molecule, nuclear force between the nuclei of the two atoms
(a) is not important because nuclear forces are short-ranged
(b) is as important as an electrostatic force for binding the two atoms
(c) cancels the repulsive electrostatic force between the nuclei
(d) is not important because the oxygen nucleus have an equal number of neutrons and protons

The correct option is: (a) is not important because nuclear forces are short-ranged

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For the ground state, the electron in the H-atom has an angular momentum =h, according to the simple Bohr model. Angular momentum is a vector and hence there will be infinitely many orbits with the vector pointing in all possible directions. In actuality, this is not true,
(a) because Bohr model gives incorrect values of angular momentum
(b) because only one of these would have a minimum energy
(c) angular momentum must be in the direction of spin of electron
(d) because electrons go around only in horizontal orbits

The correct option is: (a) because Bohr model gives incorrect values of angular momentum

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The binding energy of an H-atom, considering an electron moving around a fixed nucleus (proton), is B=\frac{m e^{4}}{8 n^{2} \epsilon_{0}^{2} h^{2}} \quad(\mathrm{~m}= electron mass ) . If one decides to work in a frame of reference where the electron is at rest, the proton would be moving around it. By similar arguments, the binding energy would be B=\frac{M e^{4}}{8 n^{2} \epsilon_{0}^{2} h^{2}} \quad (M = proton mass) This last expression is not correct because
(a) n would not be integral
(b) Bohr-quantisation applies only to electron
(c) the frame in which the electron is at rest is not inertial
(d) the motion of the proton would not be in circular orbits, even approximately

The correct option is: (c) the frame in which the electron is at rest is not inertial

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Nuclei with magic no. of proton Z=2,8,20,28,50,52 and magic no. of neutrons N=2,8,20,28,50,82 and 126 are found to be very stable
(i) Verify this by calculating the proton separation energy Sp for \operatorname Sn^ {120}(\mathrm{Z}=50) and \mathrm Sb^ {121}=(\mathrm{Z}=51). The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by \mathrm{Sp}=\left(\mathrm{M}_{\mathrm{z}-1}, \mathrm{~N}+\mathrm{M}_{\mathrm{H}}-\mathrm{M}_{\mathrm{Z}, \mathrm{N}}\right) \mathrm{c}^{2}. Given \ln ^{119}=118.9058 \mathrm{u}, \mathrm{Sn}^{120}=119.902199 \mathrm{u},  \mathrm{Sb}^{121}=120.903824 \mathrm{u},  \mathrm{H}^{1}=1.0078252 \mathrm{u}
(ii) What does the existence of magic number indicate?

i) The proton separation energy is given by, $\mathrm{SpSn}=(\mathrm{M} 119.70+\mathrm{Mh}-\mathrm{M} 120.70) \mathrm{c}^{2}=0.0114362 \mathrm{c}^{2}$ Similarly we have, $\mathrm{SpSp}=(\mathrm{M}...

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The activity \mathrm{R} of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:

    \[\begin{tabular}{|l|l|l|l|l|l|} \hline$t(\mathrm{~h})$ & 0 & 1 & 2 & 3 & 4 \\ \hline R(MBq) & 100 & $35.36$ & $12.51$ & $4.42$ & $1.56$ \\ \hline \end{tabular}\]


(i) Plot the graph of R versus t and calculate half-life from the graph.
(ii) Plot the graph of \ln \left(\mathrm{R} / \mathrm{R}_{0}\right) versus \mathrm{t} and obtain the value of half-life from the graph.

(i) Graph between $\mathrm{R}$ versus $\mathrm{t}$ will be an exponential curve. From the graph at slightly more than $\mathrm{t}=\frac{1}{2} \mathrm{~h}$ the $\mathrm{R}$ should be $50 \%$ so at...

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Before the neutrino hypothesis, the beta decay process was thought to be the transition \mathrm{n} \rightarrow \mathrm{p}+\mathrm{e}^{-}. If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.

It is given that neutron was at rest before $\beta$ decay from neutron. So, energy of neutron $=$ $\mathrm{E}_{\mathrm{n}}=\mathrm{m}_{\mathrm{n}} \mathrm{c}^{2}$. Momentum of neutron...

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The deuteron is bound by nuclear forces just as \mathrm{H}-atom is made up of \mathrm{p} and e bound by electrostatic forces. If we consider the force between neutron and proton in deuteron as given in the form of a Coulomb potential but with an effective charge \mathrm{e}^{\prime}: F=\frac{1}{4 \Pi \epsilon_{0}} \frac{e^{\prime 2}}{r} estimate the value of \left(\mathrm{e}^{\prime} / \mathrm{e}\right) given that the binding energy of a deuteron is 2.2 \mathrm{MeV}.

The binding energy of $\mathrm{H}$ atom is given as $\mathrm{E}=13.6 \mathrm{eV}$ The reduced $\mathrm{m}^{\prime}$ is given as $918 \mathrm{~m}$ The mass of a neutron or a proton is given as...

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Deuteron is a bound state of a neutron and a proton with a binding energy B = 2.2 MeV. A γ -ray of energy E is aimed at a deuteron nucleus to try to break it into a (neutron + proton) such that the n and p move in the direction of the incident γ-ray. If E = B, show that this cannot happen. Hence calculate how much bigger than B must E be for such a process to happen.

The binding energy of a deuteron is given as $B = 2.2 MeV$ The kinetic energies of neutron and proton be $K_n$ and $K_p$ $p_n$ and $p_p$ are the momentum of neutron and proton $E - B = K_n + K_p$ B...

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Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is
Sulphur^{38}\frac{\text { half-life }\longrightarrow}{=2.48 h}Cl^{38}\frac{\text { half-life }\longrightarrow}{=0.62 h}Ar^{38}(Stable)
Assume that we start with 1000 38S nuclei at time t=0. The number of Cl^{38} is of count zero at t=0 and will again be zero at t=\infty. At what value of t, would the number of counts be a maximum?

Let the disintegration constants for $S^{38}$ and $Cl^{38}$ be $\lambda_ 1$ and $\lambda_ 2$ respectively. $\mathrm dN_1 / \mathrm{dt}=-\lambda N_{1}$ $\mathrm dN_2 / \mathrm{dt}=$ rate of decay of...

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Are the nucleons fundamental particles, or do they consist of still smaller parts? One way to find out is to probe a nucleon just as Rutherford probed an atom. What should be the kinetic energy of an electron for it to be able to probe a nucleon? Assume the diameter of a nucleon to be approximately 10^{-15} \mathrm{~m}.

$\lambda=\mathrm{h} / \mathrm{p}$ and, kinetic energy $=$ potential energy $\mathrm{E}=\mathrm{hc} / \lambda$ Kinetic energy of an electron can be calculated as, $\mathrm{KE}=\mathrm{PE}=\mathrm{hc}...

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A piece of wood from the ruins of an ancient building was found to have a \mathrm{C}^{14} activity of 12 disintegrations per minute per gram of its carbon content. The C^{14} activity of the living wood is 16 disintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given the half-life of \mathrm{C}^{14} is 5760 years.

$\mathrm{C}^{14}$ activity of a piece of wood from the ruins is given as $\mathrm{R}=12 \mathrm{dis} / \mathrm{min}$ per gram $\mathrm{C}^{14}$ activity of a living wood is given as...

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Consider a radioactive nucleus A which decays to a stable nucleus \mathrm{C} through the following sequence: \mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} Here \mathrm{B} is an intermediate nuclei which is also radioactive. Considering that there are \mathrm{N}_{0} atoms of A initially, plot the graph showing the variation of number of atoms of A and B versus time.

  At $\mathrm{t}=0,$ $\mathrm{~N}_{\mathrm{A}}=\mathrm{N}_{0}$ As time passes, $N_A$ decreases exponentially, while the number of atoms in B increases, reaches its maximum, and then decays to...

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Samples of two radioactive nuclides A and B are taken. \lambda_A and \lambda_B are the disintegration constants of A and B respectively. In which of the following cases, the two samples can simultaneously have the same decay rate at any time?
(a) Initial rate of decay of A is twice the initial rate of decay of B and \lambda_A=\lambda_B
(b) Initial rate of decay of A is twice the initial rate of decay of B and \lambda _A>\lambda_B
(c) Initial rate of decay of B is twice the initial rate of decay of A and \lambda_A>\lambda_B
(d) Initial rate of decay of B is the same as the rate of decay of A at t = 2h and \lambda_B<\lambda_A

The correct options are: (b) Initial rate of decay of A is twice the initial rate of decay of B and $\lambda _A>\lambda_B$ (d) Initial rate of decay of B is the same as the rate of decay of A at...

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Fusion processes, like combining two deuterons to form a He nucleus are impossible at ordinary temperatures and pressure. The reasons for this can be traced to the fact:
(a) nuclear forces have short-range
(b) nuclei are positively charged
(c) the original nuclei must be completely ionized before fusion can take place
(d) the original nuclei must first break up before combining with each other

The correct options are: (a) nuclear forces have short-range (b) nuclei are positively charged

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In a nuclear reactor, moderators slow down the neutrons which come out in a fission process. The moderator used to have light nuclei. Heavy nuclei will not serve the purpose because
(a) they will break up
(b) elastic collision of neutrons with heavy nuclei will not slow them down
(c) the net weight of the reactor would be unbearably high
(d) substances with heavy nuclei do not occur in a liquid or gaseous state at room temperature

The correct option is: (b) elastic collision of neutrons with heavy nuclei will not slow them down

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Tritium is an isotope of hydrogen whose nucleus Triton contains 2 neutrons and 1 proton. Free neutrons decay into P+\bar{e}+\bar{v}. If one of the neutrons in Triton decays, it would transform into He3 nucleus. This does not happen. This is because
(a) Triton energy is less than that of a \mathrm{He}^{3} nucleus
(b) the electron created in the beta decay process cannot remain in the nucleus
(c) both the neutrons in triton have to decay simultaneously resulting in a nucleus with 3 protons, which is not a \mathrm{He}^{3} nucleus
(d) because free neutrons decay due to external perturbations which is absent in a triton nucleus

The correct option is: (a) Triton energy is less than that of a $\mathrm{He}^{3}$ nucleus

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Suppose we consider a large number of containers each containing initially 10000 atoms of a radioactive material with a half-life of 1 year. After 1 year
(a) all the containers will have 5000 atoms of the material
(b) all the containers will contain the same number of atoms of the material but that number will only be approximately 5000
(c) the containers will, in general, have different numbers of the atoms of the material but their average will be close to 5000
(d) none of the containers can have more than 5000 atoms

The correct option is: (c) the containers will, in general, have different numbers of the atoms of the material but their average will be close to 5000

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If the total charge enclosed by a surface is zero, does it imply that the electric field everywhere on the surface is zero? Conversely, if the electric field everywhere on a surface is zero, does it imply that net charge inside is zero.

Although a surface's total charge is zero, this does not imply that the electric field is zero everywhere on the surface; the field may be normal to the surface. In addition, it implies that the...

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A positive charge Q is uniformly distributed along a circular ring of radius R. A small test charge q is placed at the centre of the ring. Then a) if q > 0 and is displaced away from the centre in the plane of the ring., it will be pushed back towards the centre b) if q < 0 and is displaced away from the centre in the plane of the ring, it will never return to the centre and will continue moving till it hits the ring c) if q < 0, it will perform SHM for small displacement along the axis d) q at the centre of the ring is in an unstable equilibrium within the plane of the ring for q > 0

The correct options are a) if q > 0 and is displaced away from the centre in the plane of the ring., it will be pushed back towards the centre b) if q < 0 and is displaced away from the centre...

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Refer to the arrangement of charges in the figure and a Gaussian surface of radius R with Q at the centre. Then a) total flux through the surface of the sphere is –Q/ε0 b) field on the surface of the sphere is –Q/4πε0R2 c) flux through the surface of the sphere due to 5Q is zero d) field on the surface of the sphere due to -2Q is the same everywhere

The correct options are a) total flux through the surface of the sphere is –Q/ε0 c) flux through the surface of the sphere due to 5Q is zero

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Consider a region inside which there are various types of charges but the total charge is zero. At points outside the region a) the electric field is necessarily zero b) the electric field is due to the dipole moment of the charge distribution only c) the dominant electric field is proportional to 1/r3 for large r, where r is the distance from an origin in this region d) the work done to move a charged particle along a closed path, away from the region, will be zero

The correct options are c) the dominant electric field is proportional to 1/r3 for large r, where r is the distance from an origin in this region d) the work done to move a charged particle along a...

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If \oint_{s} E . d S=0 over a surface, then a) the electric field inside the surface and on it is zero b) the electric field inside the surface is necessarily uniform c) the number of flux lines entering the surface must be equal to the number of flux lines leaving it d) all charges must necessarily be outside the surface

The correct options are c) the number of flux lines entering the surface must be equal to the number of flux lines leaving it d) all charges must necessarily be outside the surface

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Five charges q_{1}, q_{2}, q_{3}, q_{4}, and q_{5} are fixed at their positions as shown in the figure. S is a Gaussian surface. The Gauss’s law is given by \oint_{s} E \cdot d C=\frac{q}{\varepsilon_{0}} \quad Which of the following statements is correct? a) E on the LHS of the above equation will have a contribution from q1, q3, and q5 while q on the RHS will have a contribution from q2 and q4 only b) E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only c) E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q1, q3, and q5 only d) both E on the LHS and q on the RHS will have contributions from q2 and q4 onlyv

The correct option is b) E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only

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A long straight cable of length I is placed symmetrically along the z-axis and has radius a. The cable consists of a thin wire and a co-axial conducting tube. An alternating current I(t)=I_{0} sin (2\pi vt) flows down the central thin wire and returns along the co-axial conducting tube. The induced electric field at a distance s from the wire inside the cable is \mathbf{E}(\mathrm{s}, \mathrm{t})=\mu_{0} \mathrm{l}_{0} \mathrm{~V} cos (2\pi vt). In \left(\frac{s}{a}\right) \hat{k},
compare the conduction current 10 with the displacement current I_{0}^{\mathrm{d}}

The displacement will be, $I_{0}^{\mathrm{d}} / \mathrm{I}_{0}=(\mathrm{am} / \lambda)^{2}$

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A long straight cable of length I is placed symmetrically along the z-axis and has radius a. The cable consists of a thin wire and a co-axial conducting tube. An alternating current I(t)=I_{0} sin (2\pi vt) flows down the central thin wire and returns along the co-axial conducting tube. The induced electric field at a distance s from the wire inside the cable is \mathbf{E}(\mathrm{s}, \mathrm{t})=\mu_{0} \mathrm{l}_{0} \mathrm{~V} cos (2\pi vt). In \left(\frac{s}{a}\right) \hat{k},
a) calculate the displacement current density inside the cable
b) integrate the displacement current density across the cross-section of the cable to find the total displacement current I

a) The displacement current density is given as $\vec{J}_{d}=\frac{2 \pi I_{0}}{\lambda^{2}} \ln \frac{a}{s} \sin 2 \pi v t \hat{k}$ b) Total displacement current will be, $I^{d}=\int J_{d} 2 \pi s...

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Seawater at frequency v=4 \times 10^8 \mathrm{~Hz} has permittivity \varepsilon=80 \varepsilon_{0}, permeability \mu=\mu_{0} and resistivity \rho= 0.25 \Omega \mathrm{m}. Imagine a parallel plate capacitor immersed in seawater and driven by an alternating voltage source V(t)=V_{0} \sin (2 \pi v t) . What fraction of the conduction current density is the displacement current density?

The separation between the plates of the capacitor is given as $V(t)=V_{0} \sin (2 \pi v t)$ Ohm's law for the conduction of current density is given as $\mathrm{J}_{0}{...

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What happens to the intensity of light from a bulb if the distance from the bulb is doubled? As a laser beam travels across the length of a room, its intensity essentially remains constant. What geometrical characteristics of the LASER beam is responsible for the constant intensity which is missing in the case of light from the bulb?

When the distance between two points is doubled, the intensity of light is reduced by one-fourth. Geometrical characteristics of the LASER are: a) unidirectional b) monochromatic c) coherent...

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Electromagnetic waves with wavelength
i) \lambda_{1} is used in satellite communication
ii) \lambda_{2} is used to kill germs in water purifies
iii) \lambda_{3} is used to detect leakage of oil in underground pipelines
iv) \lambda_{4} is used to improve visibility in runaways during fog and mist conditions
a) identify and name the part of the electromagnetic spectrum to which these radiations belong
b) arrange these wavelengths in ascending order of their magnitude
c) write one more application of each

a) i) $\lambda_{1}$ is a microwave, used in satellite communication. ii) $\lambda_{2}$ is UV rays, used in a water purifier for killing germs. iii) $\lambda_{3}$ is X-rays, used in improving the...

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The figure shows a standard two-slit arrangement with slits S1, S2. P1, P2 are the two minima points on either side of P. At P2 on the screen, there is a hole and behind P2 is a second 2- slit arrangement with slits S3, S4 and a second screen behind them;(a) There would be no interference pattern on the second screen but it would be lighted (b) The second screen would be totally dark (c) There would be a single bright point on the second screen (d) There would be a regular two-slit pattern on the second screen

The correct answer is d) there would be a regular two-slit pattern on the second screen

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The human eye has an approximate angular resolution of φ = 5.8 × 10–4 rad and a typical photo printer prints a minimum of 300 dpi (dots per inch, 1 inch = 2.54 cm). At what minimal distance z should a printed page be held so that one does not see the individual dots.

Angular separation, φ = 5.8 × 10–4 rad The average distance between the two dots = 2.54/300 = 0.85 × 10-2 cm At distance z cm, the angle subtended = 0.85 × 10-2/z Resolution angle for human = 0.85 ×...

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A polaroid (I) is placed in front of a monochromatic source. Another polaroid (II) is placed in front of this polaroid (I) and rotated till no light passes. A third polaroid (III) is now placed in between (I) and (II). In this case, will light emerge from (II)? Explain.

A monochromatic source is placed in front of polaroid (I), and polaroid (II) is positioned in front of polaroid (I) (I). The light is unaltered as it travels through the polaroid (II). The Polaroid...

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Consider a two-slit interference arrangements such that the distance of the screen from the slits is half the distance between the slits. Obtain the value of D in terms of λ such that the first minima on the screen falls at a distance D from the centre O.

The minima will occur when ∆x = S2P – S1P = (2n-1/2)λ S1P = √D2 + (D – x)2 S2P = √D2 + (D + x)2 T2P = D + x T1P = D – x [D2 + (D+x)2]-1/2 – [D2+(D-x)2]1/2 = λ/2   D =...

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Four identical monochromatic sources A, B, C, D as shown in the figure produce waves of the same wavelength λ and are coherent. Two receiver R1 and R2 are at great but equal distances from B. (i) Which of the two receivers picks up the larger signal? (ii) Which of the two receivers picks up the larger signal when B is turned off? (iii) Which of the two receivers picks up the larger signal when D is turned off? (iv) Which of the two receivers can distinguish which of the sources B or D has been turned off?

i) R2 is the larger signal. ii) When B is switched off, R1 is y = a cos ꞷt IR1 = a2/2 R2 is y = a cos ꞷt IR2 = a2/2 So, it can be said that R1 and R2 are the same. iii) When D is switched off, R1 is...

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The optical properties of a medium are governed by the relative permittivity (εr) and relative permeability (µr ). The refractive index is defined as √µr εr = n. For ordinary material εr > 0 and µr > 0 and the positive sign is taken for the square root. In 1964, a Russian scientist V. Veselago postulated the existence of material with εr < 0 and µr < 0. Since then such ‘metamaterials’ have been produced in the laboratories and their optical properties studied. For such materials n = -√µrεr. As light enters a medium of such refractive index the phases travel away from the direction of propagation. (i) According to the description above show that if rays of light enter such a medium from the air (refractive index =1) at an angle θ in 2nd quadrant, them the refracted beam is in the 3rd quadrant (ii) Prove that Snell’s law holds for such a medium

BC = √μrεr (CD-AE) BC >0; CD > AE -√μrεr AE = BC – √μrεr CD BC = √μrεr (CD – AE) AE > CD Therefore, BC < 0 ii) BC = AC sin θi CD – AE = AC sin θr BC = √μrεr AC sin θi = √μrεr AC sin θr...

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To ensure almost 100 per cent transmissivity, photographic lenses are often coated with a thin layer of dielectric material. The refractive index of this material is intermediated between that of air and glass (which makes the optical element of the lens). A typically used dielectric film is MgF2 (n = 1.38). What should the thickness of the film be so that at the centre of the visible spectrum (5500 Ao) there is maximum transmission?

IA is incident at point A, forming an incident angle I between the air and the film surface. The reflected and refracted rays are AR1 and AD, respectively. D is the point where the partial...

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Consider a 20 W bulb emitting light of wavelength 5000 A ° and shining on a metal surface kept at a distance 2m. Assume that the metal surface has work function of 2 eV and that each atom on the metal surface can be treated as a circular disk of radius 1.5 A ° . (i) Estimate no. of photons emitted by the bulb per second. [Assume no other losses] (ii) Will there be photoelectric emission? (iii) How much time would be required by the atomic disk to receive energy equal to work function (2 eV)? (iv) How many photons would atomic disk receive within time duration calculated in (iii) above? (v) Can you explain how photoelectric effect was observed instantaneously?

Given, P = 20W λ = 5000 Ao = 5000 × 10-10 m d = 2m ϕ0 = 2 eV r = 1.5 × 10-10 m No.of photon emitted per second by the bulb = n’ = dN/dt i) No.of photon emitted by bulb per second = n’ = p λ/hc = 5 ×...

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A particle A with a mass mA is moving with a velocity v and hits a particle B (mass mB) at rest (one dimensional motion). Find the change in the de Broglie wavelength of the particle A. Treat the collision as elastic.

According to the law of conservation of momentum, mAv + mB0 = mAv1 + mBv2 mA(v-v1) = mBv2 1/2 mAv2 = 1/2 mAv12 + 1/2mBv22 mA(v-v1)(v+v1) = mBv22 v1 = (mA-mB/mA+mB)v v2 = (2mA/mA+mB)v λinitial =...

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A student performs an experiment on the photoelectric effect, using two materials A and B. A plot of Vstop vs ν is given in the figure. (i) Which material A or B has a higher work function? (ii) Given the electric charge of an electron = 1.6 × 10–19 C, find the value of h obtained from the experiment for both A and B. Comment on whether it is consistent with Einstein’s theory

i) The threshold frequency of A is vOA = 5 × 1014 Hz The threshold frequency of B is vOB = 10 × 1014 Hz Work function is ϕ = hv0 ϕOA/ ϕOB = 5 × 1014/10 × 1014 < 1 ϕOA <...

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Consider an electron in front of the metallic surface at a distance d (treated as an infinite plane surface). Assume the force of attraction by the plate is given as 2 2 0 1 4 4 q πε d Calculate work in taking the charge to an infinite distance from the plate. Taking d = 0.1nm, find the work done in electron volts. [Such a force law is not valid for d < 0.1nm].

An electron is progressively moved in the picture. The distance travelled by the electron is x, and this is accomplished by the application of an external force. F = q2/4×4πε0d2 d = 0.1 nm = 10-10 m...

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Consider a thin target (10^{-2}m square, 10^{-3}m thickness) of sodium, which produces a photocurrent of 100µA when a light of intensity 100W/m2 (λ = 660nm) falls on it. Find the probability that a photoelectron is produced when a photon strikes a sodium atom. [Take density of Na = 0.97 kg/m3].

Area = 10-4 m2 Thickness = 10-3 m Current = 10-4 A Intensity = 100 W/m2 Mass = (volume)(density) = 0.97 × 10-4 gm No.of target atoms = 0.254 × 1019 Total energy = nhv Where n = 3.3 × 1016 The...

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Two particles A and B of de Broglie wavelengths λ1 and λ2 combine to form a particle C. The process conserves momentum. Find the de Broglie wavelength of the particle C. (The motion is one dimensional).

By de-Broglie wavelengths, λ=h/p p=h/ λ p1 = h/ λ1 p2 = h/ λ2 p3 = h/ λ3 There are 4 possible cases and they are: Case 1: When p1 and p2 are positive, then λ3 = λ1 λ1/ λ1+ λ2 Case 2: When p1 and p2...

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An EM wave of intensity I falls on a surface kept in vacuum and exerts radiation pressure p on it. Which of the following are true?
a) radiation pressure is \mathrm{I} / \mathrm{c} if the wave is totally absorbed
b) radiation pressure is I / c if the wave is totally reflected
c) radiation pressure is 2 \mathrm{I} / \mathrm{c} if the wave is totally reflected
d) radiation pressure is in the range I / c<p<2 I / c for real surface

The correct options are: a) radiation pressure is $\mathrm{l} / \mathrm{c}$ if the wave is totally absorbed c) radiation pressure is $2 \mathrm{l} / \mathrm{c}$ if the wave is totally reflected d)...

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There are two sources of light, each emitting with a power of 100 W. One emits X-rays of wavelength 1nm and the other visible light at 500 nm. Find the ratio of a number of photons of X-rays to the photons of visible light of the given wavelength?

Ex = hvx Ev = hvv Let nx and nv be the no.of photons from x-rays and visible light are of equal energies and they emit 100 W power. nxhvx = nvhvv nx/nv = vv/vx = λx/λv nx/nv = 1 nm/500 nm nx:nv =...

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A particle moves in a closed orbit around the origin, due to a force which is directed towards the origin. The de Broglie wavelength of the particle varies cyclically between two values λ1, λ2 with λ1>λ2. Which of the following statement are true? (a) The particle could be moving in a circular orbit with origin as centre (b) The particle could be moving in an elliptic orbit with origin as its focus (c) When the de Broglie wavelength is λ1, the particle is nearer the origin than when its value is λ2 (d) When the de Broglie wavelength is λ2, the particle is nearer the origin than when its value is λ1

The correct answers are b) The particle could be moving in an elliptic orbit with origin as its focus d) When the de Broglie wavelength is λ2, the particle is nearer the origin than when its value...

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Photons absorbed in matter are converted to heat. A source emitting n photon/sec of frequency ν is used to convert 1kg of ice at 0°C to water at 0°C. Then, the time T taken for the conversion (a) decreases with increasing n, with ν fixed (b) decreases with n fixed, ν increasing (c) remains constant with n and ν changing such that nν = constant (d) increases when the product nν increases

The correct answers are a) decreases with increasing n, with ν fixed b) decreases with n fixed, ν increasing c) remains constant with n and ν changing such that nν = constant

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An electromagnetic wave travelling along the z-axis is given as: E=E_{0} \cos (k z-\omega t). Choose the correct options from the following a) the associated magnetic field is given as B=\frac{1}{c} \hat{k} \times E=\frac{1}{\omega}(\hat{k} \times E)
b) the electromagnetic field can be written in terms of the associated magnetic field asE=c(B \times \hat{k})
c)\hat{k} \cdot E=0, \hat{k} \cdot B=0
d)\hat{k} \times E=0, \hat{k} \times B=0

a) the associated magnetic field is given as $B=\frac{1}{c} \hat{k} \times E=\frac{1}{\omega}(\hat{k} \times E)$ b) the electromagnetic field can be written in terms of the associated magnetic field...

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An electromagnetic wave travels in vacuum along z-direction: E=\left(E_{1} \hat{i}+E_{2} \hat{j}\right) \cos (k z-\omega t) \cdot Choose the correct options from the following:
a) the associated magnetic field is given as B=\frac{1}{c}\left(E_{1} \hat{i}-E_{2} \hat{j}\right) \cos (k z-\omega t)
b) the associated magnetic field is given as B=\frac{1}{c}\left(E_{1} \hat{i}-E_{2} \hat{j}\right) \cos (k z-\omega t)
c) the given electromagnetic field is circularly polarised
d) the given electromagnetic waves is plane polarised

a) the associated magnetic field is given as $B=\frac{1}{c}\left(E_{1} \hat{i}-E_{2} \hat{j}\right) \cos (k z-\omega t)$ d) the given electromagnetic waves is plane polarised

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In the LCR circuit the ac driving voltage is v = vm sin ωt.
(i) Write down the equation of motion for q (t).
(ii) At t=t_{0}, the voltage source stops and R is short-circuited. Now write down how much energy is stored in each of L and C.

i) The equation for charge motion variation with respect to time is as follows: $\mathrm{L} d^{2} q(\mathrm{t}) / \mathrm{dt}+\mathrm{R} \mathrm{dq}(\mathrm{t}) / \mathrm{dt}+\mathrm{q}(\mathrm{t})...

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For an LCR circuit driven at frequency ω, the equation reads L di/dt + Ri + q/C = vi = vm sin ꞷ t
(i) Cast the equation in the form of a conservation of energy statement
(ii) Integrate the equation over one cycle to find that the phase difference between v and i must be acute.

i) The first equation is in the form of conservation of energy ii) We get dt as positive when we integrate the equation from $0$ to $T$, which is possible when the phase difference is constant and...

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1MW power is to be delivered from a power station to a town 10 km away. One uses a pair of Cu wires of radius 0.5 cm for this purpose. Calculate the fraction of ohmic losses to power transmitted if
(i) power is transmitted at 220V. Comment on the feasibility of doing this.
(ii) a step-up transformer is used to boost the voltage to 11000 V, power transmitted, then a step-down transformer is used to bring the voltage to 220 V.

i) It is given that the power station is $10 \mathrm{~km}$ away from the town Length of the $\mathrm{Cu}$ wire is given as $\mathrm{L}=20 \mathrm{~km}=20000 \mathrm{~m}$ Resistance of $\mathrm{Cu}$...

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An electrical device draws 2kW power from AC mains (voltage 223V (rms) = 50,000 V). The current differs (lags) in phase by φ (tan φ = -3/4) as compared to voltage.
Find (i) R,
(ii) X_{c}-X_{l},
and (iii) I_{M}. Another device has twice the values for R, X_{C} and X_{L}. How are the answers affected?

Impedance is given as Z = 25 ohms $635=25R^{2}/16$ a) Resistance can be calculated as, $R=\sqrt 25\times 16=\sqrt 400=20 ohms$ b) $X_{c}-X_{l}=-3R/4=-15ohms$ c) Main current will be...

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A device ‘X’ is connected to an a.c source. The variation of voltage, current and power in one complete cycle is shown in the figure.
(a) Which curve shows power consumption over a full cycle?
(b) What is the average power consumption over a cycle?

Solution: a) The greatest amplitude of the power curve is equal to the product of the voltage and current amplitudes. As a result, curve A denotes power. b) Because the whole cycle in the graph...

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For an LCR circuit, the power transferred from the driving source to the driven oscillator is P = I2Z cos φ.
(a) Here, the power factor cos 0, 0. φ ≥ ≥ P
(b) The driving force can give no energy to the oscillator (P = 0) in some cases.
(c) The driving force cannot syphon out (P < 0) the energy out of oscillator.
(d) The driving force can take away energy out of the oscillator.

The correct options are: (a) Here, the power factor cos 0, 0. φ ≥ ≥ P (b) The driving force can give no energy to the oscillator (P = 0) in some cases. (c) The driving force cannot syphon out (P...

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