The current is represented as I = E/R+nR when the resistors are connected in series.
Current is expressed as 10I = E/(R+R/n) when the resistors are connected in parallel.
We get n = 10 by solving the two equations.
First, a set of n equal resistors of R each are connected in series to a battery of emf E and internal resistance R. A current I is observed to flow. Then the n resistors are connected in parallel to the same battery. It is observed that the current is increased 10 times. What is ‘n’?
First, a set of n equal resistors of R each are connected in series to a battery of emf E and internal resistance R. A current I is observed to flow. Then the n resistors are connected in parallel to the same battery. It is observed that the current is increased 10 times. What is ‘n’?