In the given figure, tangent PT = 12.5 cm and PA = 10 cm; find AB. contexto.140 3 years ago Solution: As is the secant and is the tangent, we have So,
![\[PAB\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-fd6ea9b32300585b24f0f0a9b5c4d49f_l3.png "Rendered by QuickLaTeX.com")
![\[PT\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7b156736902a8c71987c6b65671b0a0b_l3.png "Rendered by QuickLaTeX.com")
![\[P{{T}^{2}}~=\text{ }PA\text{ }x\text{ }PB\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-014b8edf92012ed78a684eb3ac34b3e9_l3.png "Rendered by QuickLaTeX.com")
![\[{{12.5}^{2}}~=\text{ }10\text{ }x\text{ }PB\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0188c5769d6b7627d8686905a145591b_l3.png "Rendered by QuickLaTeX.com")
![\[PB\text{ }=\text{ }\left( 12.5\text{ }x\text{ }12.5 \right)/\text{ }10\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f575f691363dc71c88c5cf899ef1a33d_l3.png "Rendered by QuickLaTeX.com")
![\[=\text{ }15.625\text{ }cm\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-65e8c63f40d0888f4adaefab9fad618f_l3.png "Rendered by QuickLaTeX.com")
![\[AB\text{ }=\text{ }PB\text{ }-\text{ }PA\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5fac461120be0f8ac9782519a04f8c19_l3.png "Rendered by QuickLaTeX.com")
![\[=\text{ }15.625\text{ }-\text{ }10\text{ }=\text{ }5.625\text{ }cm\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-38a3757058f3254ae208107e2be853b8_l3.png "Rendered by QuickLaTeX.com")
