A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

The wire’s length (l) is 3 cm or 0.03 m

The current running through it (I) is 10 A.

The magnetic field strength (B) is 0.27 T.

the angle formed by the current and the magnetic field is

the magnetic force exerted on the wire can be calculated as:

Putting the values in the above equation, we get

As a result, the magnetic force on the wire is . Fleming’s left-hand rule can be used to determine the force’s direction.