![\[\mathbf{85}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ce8cf3529bbf7d088edd3d48cb89a2dc_l3.png "Rendered by QuickLaTeX.com")
![\[\mathbf{8}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d72852d436631c1650d3154fd874ac4a_l3.png "Rendered by QuickLaTeX.com")
Solution:
We know that,
Number of pages in the book
![\[=\text{ }85\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-77ccd343ebb1e68425615b9aff06da57_l3.png "Rendered by QuickLaTeX.com")
Number of possible outcomes
![\[=\text{ }n\left( S \right)\text{ }=\text{ }85\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-132bb1851d3758b9119b56a8be11dcff_l3.png "Rendered by QuickLaTeX.com")
Out of
![\[85\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-bfa67f20f54ce4d7fa3c8cfa65f3ef14_l3.png "Rendered by QuickLaTeX.com")
pages, pages that sum up to
![\[8\text{ }=\text{ }\left\{ 8,\text{ }17,\text{ }26,\text{ }35,\text{ }44,\text{ }53,\text{ }62,\text{ }71,\text{ }80 \right\}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e84c71fc08272d9e805b134561054221_l3.png "Rendered by QuickLaTeX.com")
So, pages that sum up to
![\[8\text{ }=\text{ }n\left( E \right)\text{ }=\text{ }9\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-054aa706427a150d402b9f10005c7cdb_l3.png "Rendered by QuickLaTeX.com")
Hence, probability of choosing a page with the sum of digits on the page equals
![\[8\text{ }=\text{ }n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }9/85\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e2c05c2359c7702b4d947bd7154aa6aa_l3.png "Rendered by QuickLaTeX.com")
