A man saves ₹ 32 during the first year, ₹ 36 in the second year and in this way he increases his savings by ₹ 4 every year. Find in what time his saving will be ₹ 200.

Solution:

As per the question:
Savings for the first year is ₹ 32
Savings for the second year is ₹ 36
Every year he increases his savings by ₹ 4.
Therefore,
A.P. will be
Where, the first term is 32 and the common difference,
It is known that, is the sum of terms of an A.P
Using the formula,

Where, the first term is , the common difference is and is number of terms in an A.P.
Given that,



As a result, the man requires 5 days to save ₹200