Find the 7th term from the end in the expansion of (2×2 – 3/2x) 8.

Answer:

Consider,

T_r+1 be the 4th term from the end of the expression.

T_r+1 is (9 − 7 + 1)th term,

The term is 3rd term from the beginning.

T₃ = T₂₊₁

∴ 7^th term from the end = 4032 x¹⁰.