Find the area bounded by the curve between and contexto.140 3 years ago Solution: Graph of can be drawn as Required area Area OABO Area BCDB
![\begin{array}{l} =\int_{0}^{\pi} \sin x d x+\left|\int_{k}^{2 \pi} \sin x d x\right| \\ =[-\cos x]_{0}^{\pi}+\left|[-\cos x]_{\pi}^{2 \pi}\right| \\ =[-\cos \pi+\cos 0]+|-\cos 2 \pi+\cos \pi| \\ =1+1+|(-1-1)| \\ =2+|-2| \\ =2+2=4 \text {sq. units } \end{array}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-348864f2cec33afbd0c1eb13f06ec50c_l3.png "Rendered by QuickLaTeX.com")
