Solution:
Area of the region enclosed by the parabola, 
Point of intersection of the parabola, 
![\begin{array}{l} =\int_{-2}^{-1}(x+2) d x+\int_{-1}^{0} x^{2} d x \\ =\left[\frac{x^{2}}{2}+2 x\right]_{-2}^{-1}+\left[\frac{x^{3}}{3}\right]_{-1}^{0} \\ =\left[\frac{(-1)^{2}}{2}+2(-1)-\frac{(-2)^{2}}{2}-2(-2)\right]+\left[-\frac{(-1)^{3}}{3}\right] \\ =\left[\frac{1}{2}-2-2+4+\frac{1}{3}\right] \\ =\frac{5}{6} \text {sq. units } \end{array}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d2cf3260135a3a77ecdc9f9e0a801e44_l3.png "Rendered by QuickLaTeX.com")
Find the area of the region enclosed by the parabola 
Solution:
Area of the region enclosed by the parabola,
Point of intersection of the parabola,
