Find the roots of the given equation: contexto.140 3 years ago Given: Putting , we get: If , we get Case II: If , we get: Hence, the roots of the equation are and .
![\begin{array}{l} \frac{4 x-3}{2 x+1}=5 \\ \Rightarrow 4 x-3=5(2 x+1) \quad[\text { On cross multiplying] } \\ \Rightarrow 4 x-3=10 x+5 \\ \Rightarrow-6 x=8 \\ \Rightarrow-6 x=8 \\ \Rightarrow x=\frac{8}{6} \\ \Rightarrow x=-\frac{4}{3} \end{array}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-241a6329b47897ee42a50d4873fe0935_l3.png "Rendered by QuickLaTeX.com")
