Solution:
(i) 
Let,s take 6 as a common term therefore we obtain,
Now multiplying and dividing by 9 we obtain,
![]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-478d84af1027ee3593251b323a3fb181_l3.png "Rendered by QuickLaTeX.com")
We can write this as
![\begin{array}{l} 6 / 9[(1-1 / 10)+(1-1 / 100)+(1-1 / 1000)+\ldots+\mathrm{n} \text { terms }] \\ 6 / 9\left[\mathrm{n}-\left\{1 / 10+1 / 10^{2}+1 / 10^{3}+\ldots+\mathrm{n} \text { terms }\right\}\right] \\ 6 / 9\left[\mathrm{n}-1 / 10\left\{1-(1 / 10)^{\mathrm{n}}\right\} /\{1-1 / 10\}\right] \\ 6 / 9\left[\mathrm{n}-1 / 9\left(1-1 / 10^{n}\right)\right] \end{array}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a33c9bef3ad90bf26df12974b5155108_l3.png "Rendered by QuickLaTeX.com")
Solution:
(i)
Let,s take 6 as a common term therefore we obtain,
Now multiplying and dividing by 9 we obtain,
We can write this as
