$I=\int \frac{{{e}^{x}}}{{{e}^{x}}\left( {{e}^{x}}-1 \right)}dx$ - Noon Academy

contexto.140

3 years ago

Putting

Now putting,

Now put

therefore,

Now put

Now from equation (1) we get

Categories: CBSE, Class 12, Exercise 15A, Integration Using Partial Fractions, Maths, RS Aggarwal

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