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$2 \times 10^{8} \mathrm{~m}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if th length of this arrangement is $2.4 \mathrm{~cm}$.
$2 \times 10^{8} \mathrm{~m}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if th length of this arrangement is $2.4 \mathrm{~cm}$.
CBSE | Chemistry | Class 11 | NCERT | Structure of Atom
$2 \times 10^{8} \mathrm{~m}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if th length of this arrangement is $2.4 \mathrm{~cm}$.

Length of the arrangement $=2.4 \mathrm{~cm}$
No. carbon atoms present $=2 \times 10^{8}$
The diameter of the carbon atom $=\frac{2.4 \times 10^{-2} m}{2 \times 10^{8} m}$
$=1.2 \times 10^{-10} m \therefore$ Radius of carbon atom $=\frac{\text { Diameter }}{2}$
$=\frac{1.2 \times 10^{-10} \mathrm{~m}}{2}$
$=6.0 \times 10^{-11} \mathrm{~m}$

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