Previous Year Question Papers

At a certain location in Africa, a compass points $12^{\circ}$ west of the geographic north. The north tip of the magnetic needle of a dip circle placed in the plane of magnetic meridian points above the horizontal. The horizontal component of the earth’s field is measured to be $0.16 \mathrm{G} .$ Specify the direction and magnitude of the earth’s field at the location.At a certain location in Africa, a compass points $12^{\circ}$ west of the geographic north. The north tip of the magnetic needle of a dip circle placed in the plane of magnetic meridian points above the horizontal. The horizontal component of the earth’s field is measured to be $0.16 \mathrm{G} .$ Specify the direction and magnitude of the earth’s field at the location.

Ans: In the above question it is given that: Angle of declination, $\theta=12^{\circ}$ Angle of dip, $\delta=60^{\circ}$ Horizontal component of earth's magnetic field, $B_{H}=0.16 \mathrm{G}$...

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Two wires of equal lengths are bent in the form of two loops. One of the loops is square shaped whereas the other loop is circular. These are suspended in a uniform magnetic field and the same current is passed through them. Which loop will experience greater torque? Give reasons.

Ans: We know the expression for torque as, $$ \begin{array}{l} \tau=\mathrm{NIAB} \\ \Rightarrow \tau \propto \mathrm{A} \end{array} $$ Since, we know that the area of circular loops is more than...

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In a Van de Graaff type generator a spherical metal shell is to be a $15 \times 10^{6} \vee$ electrode. The dielectric strength of the gas surrounding the electrode is $5 \times 10^{7} \mathrm{Vm}^{-1}$. What is the minimum radius of the spherical shell required? (You will learn from this exercise why one cannot build an electrostatic generator using a very small shell which requires a small charge to acquire a high potential.)

Ans: Given that, Potential difference is given as, $V=15 \times 10^{6} \mathrm{~V}$ Dielectric strength of the surrounding gas $=5 \times 10^{\top} \mathrm{Vm}^{-1}$ Electric field intensity is...

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A parallel plate capacitor with air between the plates has a capacitance of 8pF $\left(1 \mathrm{pF}=10^{-12} \mathrm{~F}\right)$. What will be the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 6 ?

Ans: For air, capacitance can be expressed as, $C_{0}=\frac{A \in_{0}}{d}$ $$ C_{0}=8 \times p F=8 \times 10^{-12} F $$ Now $d^{\prime}=\frac{d}{2}$ and $K=6$ $$ \begin{array}{l} \Rightarrow...

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A sphere $S_{1}$ of radius $R_{1}$ encloses a charge $\mathbf{Q} .$ If there is another concentric sphere $S_{2}$ of radius $R_{2}\left(R_{2}>R_{1}\right)$ and there is no additional change between $S_{1}$ and $s_{2}$, then find the ratio of electric flux through $s_{1}$ and $s_{2}$. $\underline{S}_{2}$

Ans: We may recall that the expression for electric flux through a surface enclosing charge q by Gauss's law is given by, $$ \phi=\frac{q}{E_{0}} $$ Where, $\varepsilon_{0}$ is the permittivity of...

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A sphere $S_{1}$ of radius $R_{1}$ encloses a charge $\mathbf{Q} .$ If there is another concentric sphere $S_{2}$ of radius $R_{2}\left(R_{2}>R_{1}\right)$ and there is no additional change between $S_{1}$ and $s_{2}$, then find the ratio of electric flux through $s_{1}$ and $s_{2}$. $\underline{S}_{2}$

Ans: We may recall that the expression for electric flux through a surface enclosing charge q by Gauss's law is given by, $$ \phi=\frac{q}{E_{0}} $$ Where, $\varepsilon_{0}$ is the permittivity of...

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When a glass rod is rubbed with a silk cloth, charges appear on both. A similar phenomenon is observed with many other pairs of bodies. Explain how this observation is consistent with the law of conservation of charge. Ans: Rubbing is a phenomenon in which there is production of charges equal in

Ans: Since unlike charges attract and like charges repel each other, the particles 1 and 2 moving towards the positively charged plate are negatively charged whereas the particle 3 that moves...

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The reaction, $\mathrm{Cr}_{2} \mathrm{O}_{3}+2 \mathrm{Al} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+2 \mathrm{Cr}\left(\Delta G^{\theta}=-421 \mathrm{~kJ}\right)$ is thermodynamically feasible as is apparent from the Gibbs energy value. Why does it not take place at room temperature?

Solution This is explained on the basis of $\mathrm{Keq}$, the equilibrium constant. In the given redox reaction, all reactants and products are solids at room temperature, so, there is no...

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$\mathrm{FeSO}_{4}$ solution mixed with $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}$, solution in $1: 1$ molar ratio gives the test of $\mathrm{Fe}^{2+}$ ion but $\mathrm{CuSO}_{4}$ solution mixed with aqueous ammonia in $1: 4$ molar ratio does not give the test of $\mathrm{Cu}^{2+}$ ion. Explain. why?

Ans: Let us see the reactions happening in both the cases. $$ \begin{array}{l} \left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}+\mathrm{FeSO}_{4}+6 \mathrm{H}_{2} \mathrm{O} \rightarrow...

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A solution of glucose in water is labelled as $10 \% \mathrm{w} / \mathrm{w}$, that would be the molality and mole fraction of each component in the solution? If the density of solution is $1.2 \mathrm{~g} \mathrm{~mL}^{-1}$ then what shall be the molarity of the

Solution 10 percent $w / w$ solution of glucose in water means $10 g$ glucose and $90 \mathrm{~g}$ of water. $10 \mathrm{~g}$ of glucose $=\frac{10}{180}=0.0555$ moles And $90 \mathrm{~g}$ of...

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‘Stability of crystal is reflected in the magnitude of its melting point’. Comment. Collect melting points of solid water, ethyl alcohol, diethyl ether and methane from a data book. What can you say about the intermolecular forces between these molecules?

Ans: Higher the melting point, greater are the intermolecular forces of attraction between the atoms of a molecule and greater is the stability of that molecule. A substance with higher melting...

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Stability of crystal is reflected in the magnitude of its melting point’. Comment. Collect melting points of solid water, ethyl alcohol, diethyl ether and methane from a data book. What can you say about the intermolecular forces between these molecules?

Ans: Higher the melting point, greater are the intermolecular forces of attraction between the atoms of a molecule and greater is the stability of that molecule. A substance with higher melting...

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Two particles each of mass $\mathrm{m}$ and carrying charge $\mathrm{Q}$ are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces, then $Q / m$ (in $\mathrm{C} / \mathrm{Kg}$ ) is of the order of:
A $10^{-6}$
B $10^{-10}$
(C) $10^{-15}$
D $10^{-20}$

Correct option is (B) $10^{-10}$ Given : Gravitational force $=$ Electrostatics force Let the distance between the rwo charges be r. $$ \begin{array}{l} \Rightarrow \frac{\mathrm{G}(\mathrm{m})...

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A parallel-plate air condenser of plate area A and separation d is charged to potential V and then the battery is removed. Now a slab of dielectric constant k is introduced between the plates. If Q, E, and W denote respectively the magnitude of the charge on each plate, the electric field between the plates (after the introduction of the dielectric slab) and work done on the system in the process of introducing the slab, then
A $\quad W=\frac{\xi_{10} \mathrm{~A} \mathrm{~V} \mathrm{~h}^{2}}{2 \mathrm{~d}}(1-1 / \mathrm{k})$
B $\quad Q=\frac{\xi_{1} K_{A} V}{d}$
c $\quad Q=\frac{\xi_{11} \mathrm{~A} \mathrm{~V}}{\mathrm{~d}}$
$\mathrm{D} \quad \mathrm{E}=\frac{\mathrm{V}}{\mathrm{kd}}$

Correct option is A $\mathrm{W}=\frac{\varepsilon_{0} \mathrm{~A} \mathrm{~V} \mathrm{~h}^{2}}{2 \mathrm{~d}}(1-1 / \mathrm{k})$ C $Q=\frac{\varepsilon_{0} A V}{d}$ D $\quad E=\frac{V}{k d}$ As...

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A parallel plate capacitor with a dielectric slab of dielectric constant 3, filling the space between the plates, is charged to a potential V. The battery is then disconnected and the dielectric slab is withdrawn. It is then replaced by another dielectric slab of dielectric constant 2. If the energies stored in the capacitor before and after the dielectric slab is changed are $\mathrm{E}_{1}$ and $\mathrm{E}_{2}$, then $\mathrm{E}_{1} / \mathrm{E}_{2}$ is:
A $\frac{4}{9}$
B $\frac{2}{3}$
c $\frac{3}{2}$
D $\frac{9}{5}$

Correct option is B $\frac{2}{3}$ Let the charge stored by a capacitor with dielectric constant 3 be $Q$. Thus energy stored be $\frac{\mathrm{Q}^{2}}{2 \mathrm{C}_{1}}$ Since the charge remains the...

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Quality factor of series resonance circuit is given by
A $\frac{\mathrm{f}_{2}-\mathrm{f}_{1}}{\mathrm{f}_{0}}$
B $\mathrm{f}_{2}-\mathrm{f}_{1}$
c) $\frac{\mathrm{f}_{1}-\mathrm{f}_{0}}{\mathrm{f}_{2}}$
D $\frac{\mathrm{f}_{0}}{\mathrm{f}_{2}-\mathrm{f}_{1}}$

Correct option is D $\frac{\mathrm{f}_{0}}{\mathrm{f}_{2}-\mathrm{f}_{1}}$ Quality factor is a relation between stored energy and energy dissipation in a device or system. As per definition of...

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The frequency at which the impedance of the circuit boorens mavimum is
a $\frac{1}{2 \pi} \sqrt{\frac{1}{L C}+\frac{R^{2}}{L^{2}}}$
b $\frac{1}{2 \pi} \frac{1}{\sqrt{1 C}}$
c $\frac{1}{2 \mathrm{z}} \sqrt{\frac{1}{\mathrm{LC}}-\frac{\mathrm{R}^{2}}{\mathrm{~L}^{2}}}$
D $\frac{1}{2 \mathrm{e}} \frac{\mathrm{R}}{\mathrm{L}}$

Correct option is c $\frac{1}{2 \pi} \sqrt{\frac{1}{L C}-\frac{R^{2}}{L^{2}}}$ Megritude of admittanos $Y=\frac{1}{Z}$ is given by: $$ |\mathrm{Y}|=\frac{\mid \mathrm{H}^{2}...

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The frequency at which the impedance of the circuit boorens mavimum is
a $\frac{1}{2 \pi} \sqrt{\frac{1}{L C}+\frac{R^{2}}{L^{2}}}$
b $\frac{1}{2 \pi} \frac{1}{\sqrt{1 C}}$
c $\frac{1}{2 \mathrm{z}} \sqrt{\frac{1}{\mathrm{LC}}-\frac{\mathrm{R}^{2}}{\mathrm{~L}^{2}}}$
D $\frac{1}{2 \mathrm{e}} \frac{\mathrm{R}}{\mathrm{L}}$

Correct option is c $\frac{1}{2 \pi} \sqrt{\frac{1}{L C}-\frac{R^{2}}{L^{2}}}$ Megritude of admittanos $Y=\frac{1}{Z}$ is given by: $$ |\mathrm{Y}|=\frac{\mid \mathrm{H}^{2}...

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The resonent froquengy in an anti resonant circuitis:
a $\frac{1}{2 \mathrm{~s} \sqrt{L C}}$
b $\frac{1}{2 \mathrm{~s}} \sqrt{\frac{1}{\mathrm{LC}}-\frac{\mathrm{R}^{2}}{\mathrm{~L}^{2}}}$
c $\frac{1}{2 \mathrm{~s}} \sqrt{1 . \mathrm{C}}$
D $\frac{1}{2 \pi} \sqrt{\frac{C}{L}}$

Correct option is a $\frac{1}{2 \pi \sqrt{L C}}$ For rescnance $$ \mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{E}} $$ $$ \begin{aligned} \mathrm{kL} &=\frac{1}{\mathrm{wC}} \\ \mathrm{w}...

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An element with molar mass $2.7 \times 10^{-2} \mathrm{~kg} \mathrm{~mol}^{-1}$ forms a cubic unit cell with an edge length $405 \mathrm{pm}$. If its density is $2.7 \times 10^{3} \mathrm{~kg} \mathrm{~m}^{-3}$ what is the nature of the cubic unit cell?

Ans: It is given that density of the element, $d=2.7 \times 10^{3} \mathrm{~kg} \mathrm{~m}^{-3}$ Molar mass, $M=2.7 \times 10^{-2} \mathrm{~kg} \mathrm{~mol}^{-1}$ Edge length, $\mathrm{a}=405...

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Heny’s law constant for $\mathrm{CO}_{2}$ in water is $1.67 \times 10_{8} \mathrm{~Pa}$ at $298 \mathrm{~K}$. Calculate the quantity of $\mathrm{CO}_{2}$ in $500 \mathrm{~mL}$ of soda water when packed under $2.5 \mathrm{~atm} \mathrm{CO}_{2}$ pressure at $298 \mathrm{~K}$.

Solution 7: $$ \mathrm{KH}=1.67 \times 10_{8} \mathrm{~Pa} $$ $$ \begin{array}{l} \hline P_{A}^{o}=450 \mathrm{~mm}, P_{B}^{o}=700 \mathrm{~mm}, P_{\text {total }}=600 \mathrm{~mm} \\ \text { As...

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Arrange the following in increasing order of their basic strength: i. $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}, \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}, \mathrm{NH}_{3}, \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{NH}_{2} \&\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}$

Ans: Considering the inductive effect of alkyl groups $\mathrm{NH}_{3}, \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}$ and $\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}$ can be...

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An organic compound with the molecular formula $\mathrm{C}, \mathrm{H}_{10} \mathrm{O}$ forms 2,4 -DNP derivative, reduces Tollens’ reagent and undergoes Cannizzaro reaction. On vigorous oxidation, it gives 1,2 -benzenedicarboxylic acid. Identify the compound.

Ans: It is because the chemical $\left(\mathrm{C}_{9} \mathrm{H}_{10} \mathrm{O}\right)$ generates a derivative of 2,4 -dnp and reduces the reagent of Tollen. The chemical must thus be an aldehyde....

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