Previous Year Question Papers

At a certain location in Africa, a compass points $12^{\circ}$ west of the geographic north. The north tip of the magnetic needle of a dip circle placed in the plane of magnetic meridian points above the horizontal. The horizontal component of the earth’s field is measured to be $0.16 \mathrm{G} .$ Specify the direction and magnitude of the earth’s field at the location.At a certain location in Africa, a compass points $12^{\circ}$ west of the geographic north. The north tip of the magnetic needle of a dip circle placed in the plane of magnetic meridian points above the horizontal. The horizontal component of the earth’s field is measured to be $0.16 \mathrm{G} .$ Specify the direction and magnitude of the earth’s field at the location.

Ans: In the above question it is given that: Angle of declination, $\theta=12^{\circ}$ Angle of dip, $\delta=60^{\circ}$ Horizontal component of earth's magnetic field, $B_{H}=0.16 \mathrm{G}$...

read more

Two wires of equal lengths are bent in the form of two loops. One of the loops is square shaped whereas the other loop is circular. These are suspended in a uniform magnetic field and the same current is passed through them. Which loop will experience greater torque? Give reasons.

Ans: We know the expression for torque as, $$ \begin{array}{l} \tau=\mathrm{NIAB} \\ \Rightarrow \tau \propto \mathrm{A} \end{array} $$ Since, we know that the area of circular loops is more than...

read more

In a Van de Graaff type generator a spherical metal shell is to be a $15 \times 10^{6} \vee$ electrode. The dielectric strength of the gas surrounding the electrode is $5 \times 10^{7} \mathrm{Vm}^{-1}$. What is the minimum radius of the spherical shell required? (You will learn from this exercise why one cannot build an electrostatic generator using a very small shell which requires a small charge to acquire a high potential.)

Ans: Given that, Potential difference is given as, $V=15 \times 10^{6} \mathrm{~V}$ Dielectric strength of the surrounding gas $=5 \times 10^{\top} \mathrm{Vm}^{-1}$ Electric field intensity is...

read more

A parallel plate capacitor with air between the plates has a capacitance of 8pF $\left(1 \mathrm{pF}=10^{-12} \mathrm{~F}\right)$. What will be the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 6 ?

Ans: For air, capacitance can be expressed as, $C_{0}=\frac{A \in_{0}}{d}$ $$ C_{0}=8 \times p F=8 \times 10^{-12} F $$ Now $d^{\prime}=\frac{d}{2}$ and $K=6$ $$ \begin{array}{l} \Rightarrow...

read more

A sphere $S_{1}$ of radius $R_{1}$ encloses a charge $\mathbf{Q} .$ If there is another concentric sphere $S_{2}$ of radius $R_{2}\left(R_{2}>R_{1}\right)$ and there is no additional change between $S_{1}$ and $s_{2}$, then find the ratio of electric flux through $s_{1}$ and $s_{2}$. $\underline{S}_{2}$

Ans: We may recall that the expression for electric flux through a surface enclosing charge q by Gauss's law is given by, $$ \phi=\frac{q}{E_{0}} $$ Where, $\varepsilon_{0}$ is the permittivity of...

read more

A sphere $S_{1}$ of radius $R_{1}$ encloses a charge $\mathbf{Q} .$ If there is another concentric sphere $S_{2}$ of radius $R_{2}\left(R_{2}>R_{1}\right)$ and there is no additional change between $S_{1}$ and $s_{2}$, then find the ratio of electric flux through $s_{1}$ and $s_{2}$. $\underline{S}_{2}$

Ans: We may recall that the expression for electric flux through a surface enclosing charge q by Gauss's law is given by, $$ \phi=\frac{q}{E_{0}} $$ Where, $\varepsilon_{0}$ is the permittivity of...

read more

When a glass rod is rubbed with a silk cloth, charges appear on both. A similar phenomenon is observed with many other pairs of bodies. Explain how this observation is consistent with the law of conservation of charge. Ans: Rubbing is a phenomenon in which there is production of charges equal in

Ans: Since unlike charges attract and like charges repel each other, the particles 1 and 2 moving towards the positively charged plate are negatively charged whereas the particle 3 that moves...

read more

Two particles each of mass $\mathrm{m}$ and carrying charge $\mathrm{Q}$ are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces, then $Q / m$ (in $\mathrm{C} / \mathrm{Kg}$ ) is of the order of:
A $10^{-6}$
B $10^{-10}$
(C) $10^{-15}$
D $10^{-20}$

Correct option is (B) $10^{-10}$ Given : Gravitational force $=$ Electrostatics force Let the distance between the rwo charges be r. $$ \begin{array}{l} \Rightarrow \frac{\mathrm{G}(\mathrm{m})...

read more

A parallel-plate air condenser of plate area A and separation d is charged to potential V and then the battery is removed. Now a slab of dielectric constant k is introduced between the plates. If Q, E, and W denote respectively the magnitude of the charge on each plate, the electric field between the plates (after the introduction of the dielectric slab) and work done on the system in the process of introducing the slab, then
A $\quad W=\frac{\xi_{10} \mathrm{~A} \mathrm{~V} \mathrm{~h}^{2}}{2 \mathrm{~d}}(1-1 / \mathrm{k})$
B $\quad Q=\frac{\xi_{1} K_{A} V}{d}$
c $\quad Q=\frac{\xi_{11} \mathrm{~A} \mathrm{~V}}{\mathrm{~d}}$
$\mathrm{D} \quad \mathrm{E}=\frac{\mathrm{V}}{\mathrm{kd}}$

Correct option is A $\mathrm{W}=\frac{\varepsilon_{0} \mathrm{~A} \mathrm{~V} \mathrm{~h}^{2}}{2 \mathrm{~d}}(1-1 / \mathrm{k})$ C $Q=\frac{\varepsilon_{0} A V}{d}$ D $\quad E=\frac{V}{k d}$ As...

read more

A parallel plate capacitor with a dielectric slab of dielectric constant 3, filling the space between the plates, is charged to a potential V. The battery is then disconnected and the dielectric slab is withdrawn. It is then replaced by another dielectric slab of dielectric constant 2. If the energies stored in the capacitor before and after the dielectric slab is changed are $\mathrm{E}_{1}$ and $\mathrm{E}_{2}$, then $\mathrm{E}_{1} / \mathrm{E}_{2}$ is:
A $\frac{4}{9}$
B $\frac{2}{3}$
c $\frac{3}{2}$
D $\frac{9}{5}$

Correct option is B $\frac{2}{3}$ Let the charge stored by a capacitor with dielectric constant 3 be $Q$. Thus energy stored be $\frac{\mathrm{Q}^{2}}{2 \mathrm{C}_{1}}$ Since the charge remains the...

read more

Quality factor of series resonance circuit is given by
A $\frac{\mathrm{f}_{2}-\mathrm{f}_{1}}{\mathrm{f}_{0}}$
B $\mathrm{f}_{2}-\mathrm{f}_{1}$
c) $\frac{\mathrm{f}_{1}-\mathrm{f}_{0}}{\mathrm{f}_{2}}$
D $\frac{\mathrm{f}_{0}}{\mathrm{f}_{2}-\mathrm{f}_{1}}$

Correct option is D $\frac{\mathrm{f}_{0}}{\mathrm{f}_{2}-\mathrm{f}_{1}}$ Quality factor is a relation between stored energy and energy dissipation in a device or system. As per definition of...

read more

The frequency at which the impedance of the circuit boorens mavimum is
a $\frac{1}{2 \pi} \sqrt{\frac{1}{L C}+\frac{R^{2}}{L^{2}}}$
b $\frac{1}{2 \pi} \frac{1}{\sqrt{1 C}}$
c $\frac{1}{2 \mathrm{z}} \sqrt{\frac{1}{\mathrm{LC}}-\frac{\mathrm{R}^{2}}{\mathrm{~L}^{2}}}$
D $\frac{1}{2 \mathrm{e}} \frac{\mathrm{R}}{\mathrm{L}}$

Correct option is c $\frac{1}{2 \pi} \sqrt{\frac{1}{L C}-\frac{R^{2}}{L^{2}}}$ Megritude of admittanos $Y=\frac{1}{Z}$ is given by: $$ |\mathrm{Y}|=\frac{\mid \mathrm{H}^{2}...

read more

The resonent froquengy in an anti resonant circuitis:
a $\frac{1}{2 \mathrm{~s} \sqrt{L C}}$
b $\frac{1}{2 \mathrm{~s}} \sqrt{\frac{1}{\mathrm{LC}}-\frac{\mathrm{R}^{2}}{\mathrm{~L}^{2}}}$
c $\frac{1}{2 \mathrm{~s}} \sqrt{1 . \mathrm{C}}$
D $\frac{1}{2 \pi} \sqrt{\frac{C}{L}}$

Correct option is a $\frac{1}{2 \pi \sqrt{L C}}$ For rescnance $$ \mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{E}} $$ $$ \begin{aligned} \mathrm{kL} &=\frac{1}{\mathrm{wC}} \\ \mathrm{w}...

read more

A circular coil a carrying current produces a magnetic field $\mathrm{B}_{0}$ at its centre. This coil is made itself to 10 turns and the same current is set up in it. The magnetic field $\mathrm{B}$ at its centre would be
A $\quad \mathrm{B}=\mathrm{B}_{0}$
B $\quad \mathrm{B}=10 \mathrm{~B}_{0}$
C $\quad \mathrm{B}=50 \mathrm{~B}_{0}$
D $\quad B=100 B_{0}$

Correct option is B $\mathrm{B}=10 \mathrm{~B}_{0}$ Electric current in a circular loop creates a magnetic field which is more concentrated in the center of the loop than outside the loop....

read more

An electric current i is flowing in a circular coil of radius a. At what distance from the center of the axis of the coil will the magnetic field be $\frac{1}{8}$ of its value at the centre?
A $3 \mathrm{a}$
в $\sqrt{3} a$
c $\frac{\mathrm{a}}{3}$
D $\frac{\mathrm{a}}{\sqrt{3}}$

Correct option is B $\sqrt{3} \mathrm{a}$ Magnetic field due to the circular current (I) carrying coil of radius $\mathrm{a}$, at a distance $r$ from the center of the coil is given by: $$...

read more

An ammeter of resistance $0.2 \Omega$ and range $10 \mathrm{~mA}$ is to be used to read potential difference upto 1 volt. It will have to be connected to A $99.8 \Omega$ resistance in series B $99.8 \Omega$ resistance in parallel C $0.1 \Omega$ resistance in parallel D $0.1 \Omega$ resistance in series

Correct option is A $99.8 \Omega$ resistance in series $$ \begin{array}{l} \mathrm{V}=\mathrm{I}_{g}\left(\mathrm{R}+\mathrm{R}_{g}\right) \\ \therefore 1=10 \times 10^{-3} \times(\mathrm{R}+0.2) \\...

read more

The resistance required to be connected in parallel to an ammeter in order to increase its range 10 times, will be
A one-tenth the resistance of ammeter
B nine times the resistance of ammeter

C ten times the resistance of ammeter
D one-ninth the resistance of ammeter

Correct option is D one-ninth the resistance of ammeter Full scale deflection voltage be V Now initiall range is I $$ \mathrm{V}=\mathrm{IR} $$ Now, Range is made $10 \mathrm{I}$ $$ \begin{array}{l}...

read more

In the order of increasing frequency, the electromagnetic spectrum may be arranged as
A Gamma rays, $\mathrm{X}$-rays, visible light, radio waves
B $\mathrm{X}$-rays $_{7}$ gamma rays, visible light, radio waves
C Radio waves, visible light, $\mathrm{X}$-rays, gamma rays
D Radio waves, visible light, gamma rays, $\mathrm{X}$-rays

Correct option is C Radio waves, visible light, $\mathrm{X}$-rays, gamma rays The electromagnetic spectrum is a continuum of all electromagnetic waves arranged according to frequency and wavelength....

read more

Two charges $5 \times 10^{-8} \mathrm{C}$ and $-3 \times 10^{-8} \mathrm{C}$ are located $16 \mathrm{~cm}$ apart. At what point $(\mathrm{s})$ on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

Let $\mathrm{p}$ be the point of zero potential be $\mathrm{p}$ at distance $\mathrm{r}$ from the charge $1 .$ $\mathrm{d}=16 \mathrm{~cm}$ Electric potential, $\mathrm{v}=\mathrm{q}_{1} / 4 \pi...

read more

An electric dipole has the magnitude of its charge as q and its dipole moment is p. It is placed in uniform electric field E. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively
A q.E and max
B $\quad 2 q . E$ and $\min$.
C q.E and $\min$
D zero and min.

Correct option is D zero and min. When the dipole is in the direction of field then net force is $\mathrm{q} \mathrm{E}+(-\mathrm{q} \mathrm{E})=0$ and its potential energy is minimum $=-$ p.E...

read more

1) The Bohr atomic model hypothesis made correct predictions for lower sized atoms like hydrogen, but poor spectrum predictions were achieved when larger atoms were taken into account. 2) When the spectral line is split into numerous components in the presence of a magnetic field, it fails to explain the Zeeman phenomenon.

1) The Bohr atomic model hypothesis made correct predictions for lower sized atoms like hydrogen, but poor spectrum predictions were achieved when larger atoms were taken into account. 2) When the...

read more

If the instantaneous magnetic flux and induced emf produced in a coil is $\phi$ and $\mathrm{E}$ respectively, then according to Faraday’s law of electro magnetic induction:
A $\quad$ E must be zero if $\phi=0$ and changing
B $\quad E \neq 0$ if $\phi=0$
C $E \neq 0$ if $\phi$ is changing.
D $E=0$ then $\phi$ must be zero

Correct option is c $E \neq 0$ if $\phi$ is changing. Farady's law states that time varying magnetic flux can induce an e.m.f. $\mathrm{E}=$ Electric field, Induced $$ \mathrm{E}=-\frac{\mathrm{d}...

read more

If the instantaneous magnetic flux and induced emf produced in a coil is $\phi$ and $E$ respectively, then according to Faraday’s law of electro magnetic induction:
A E must be zero if $\phi=0$ and changing
B $\quad E \neq 0$ if $\phi=0$
c $E \neq 0$ if $\phi$ is changing.
D $E=0$ then $\phi$ must be zero

Correct option is c $E \neq 0$ if $\phi$ is changing. Farady's law states that time varying magnetic flux can induce an e.m.f. $\mathrm{E}=$ Electric field, Induced $$ \mathrm{E}=-\frac{\mathrm{d}...

read more

Consider the following statements :
(i) Soft iron conducts electricity
(ii) Soft iron is magnetic material
(iii) Soft iron is used for magnetic permanent magnets
(iv) Soft iron is used as electro magnet
A (i) and (ii) are correct
B (i) and (iii) are correct
C (ii) and (iv) are correct
D (i), (ii) and (iv) are correct

Correct option is D (i), (ii) and (iv) are correct Soft iron conducts electricity It is a magnetic material It is not used for magnetic permanent magnets It is used as electro magnet

read more

Two thin, long, parallel wires, separated by a distance ‘ $\mathrm{d}$ ‘ carry a current of ‘ $\mathrm{i}$ ‘ $\mathrm{A}$ in the same direction. They will
A repel each other with a force of $y_{0} \mathrm{i}^{2} /(2 \pi \mathrm{d})$
B attract each other with a force of $\mu_{n} \mathrm{i}^{2} /(2 \pi \mathrm{d})$
C repel each other with a force of $y_{0} i^{2} /\left(2 \pi \mathrm{rd}^{2}\right)$
D attract each other with a force of $\mu_{\mu_{1}} 1^{2} /\left(2 \pi \mathrm{d}^{2}\right)$

Correct option is B attract each other with a force of $y_{0} i^{2} /(2 \pi \mathrm{d})$ $$ \frac{\mathrm{F}}{\mathrm{l}}=\frac{\mu_{0} \mathrm{i}_{1} \mathrm{i}_{2}}{2 \pi \mathrm{d}} $$ $$...

read more

Two very long straight parallel wires carry steady currents i and $2 \mathrm{i}$ in opposite directions. The distance between the wires is $\mathrm{d}$. at a certain instant of time, a point charge $\mathrm{q}$ is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity $\vec{v}$ is perpendicular to this plane. The magnitude of the force, due to the magnetic field acting on the charge at this instant is:
A $\frac{\mu_{n} i q v}{2 \pi d}$
B $\frac{\mu_{n} \text { iqv }}{\pi d}$
C $\frac{3 \mu_{n} \mathrm{iqv}}{2 \pi \mathrm{d}}$
D zero

Correct option is (D) zero Magnetic field at P is perpendicu;ar to paper inward due to both the wires. Charged particle is also projected in the same direction. So, force on the charged particle is...

read more

A Carnot engine, having an efficiency of $\eta=\frac{1}{10}$ as heat engine, is used as a. refrigerator. If the work done on the system is $10 \mathrm{~J}$, the amount of energy absorbed from the reservoir at lower temperature is:
A $90 \mathrm{~J}$
B $1 \mathrm{~J}$
c $100 \mathrm{~J}$
D $99 \mathrm{~J}$

Correct option is A $90 \mathrm{~J}$ efficiency of carnot cycle is given as $$ \eta=\frac{W}{Q_{H}} $$ where $W$ is work done and $Q_{H}$ is amount of heat added to system. $$ \begin{array}{l}...

read more

Two identical sonometer wires have a fundamental frequency of $500 \mathrm{~Hz}$, when kept under the same tension. What fractional increase in the tension of one wire would cause an occurrence of 5 beats $/ \mathrm{sec}$, when both wires vibrate together?
A 2
B 3
C 4
D 5

Solution (A) 2 $\mathrm{n} \propto \mathrm{V}$ and $\mathrm{V} \propto \sqrt{T}$ $$ \Rightarrow \mathrm{n} \propto \sqrt{\mathrm{T}} . .(1) $$ 5 beats/sec are obtained when the frequency of one...

read more

The equation of simple harmonic wave is given by $y=6 \sin 2 \pi(2 t-0.1 x)$, where $x$ and $y$ are in $m m$ and $t$ is in seconds . The phase difference between two particles $2 \mathrm{~mm}$ apart at any instant is
A $18^{0}$
B $36^{\circ}$
C $54^{0}$
D $72^{0}$

Correct option is D $72^{\circ}$ Given equation can be written as $y=6 \sin (4 \pi t-0.2 \pi x)$ $\therefore$ Phase $\phi=-0.2 \pi x$ $\Rightarrow \phi_{1}=-0.2 \pi \mathrm{x}_{1}$ and...

read more

At what temperature the average translational $\mathrm{KE}$ of the molecules of a gas will become equal to the $\mathrm{KE}$ of an electron accelerated from rest through $1 \mathrm{~V}$ potential difference?
A $\quad 10^{6} \mathrm{~K}$
B $2.34 \times 10^{4} \mathrm{~K}$
c $7.73 \times 10^{3} \mathrm{~K}$
D none of these

Correct option is C $7.73 \times 10^{3} \mathrm{~K}$ $$ \frac{3}{2} \mathrm{KT}=1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J} $$ Or" $$ \mathrm{T}=\frac{2 \times 1.6 \times 10^{-19}}{3 \times 1.38...

read more

The elastic energy stored per unit volume in a stretched wire is
A $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}}$
B $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}}$ ,br>C $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}^{2}}$
D $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}^{2}}$

Correct option is B $\frac{1(\text { stress })^{2}}{2}$ The elastic energy stored per unit volume in a stretched wire is $$ \mathrm{u}=\frac{1}{2} \times \text { stress } \times...

read more

. The linear density of a vibrating string is $1.3 \times 10^{-4} \mathrm{~kg} / \mathrm{m} . \mathrm{A}$ transverse wave is propagating on the string and is described by the equation $\mathrm{Y}=0.021 \sin (\mathrm{x}+3 \circ \mathrm{t})$ where $\mathrm{x}$ and $\mathrm{y}$ are measured in meter and t in second. Ten sion in the string is
A $\quad 0.12 \mathrm{~N}$
B $\quad 0.48 \mathrm{~N}$
C $1.20 \mathrm{~N}$
D $4.8 \mathrm{oN}$

Correct option is A $0.12 \mathrm{~N}$ Linear density $\mu=1.3 \times 10^{4} \mathrm{Kg} / \mathrm{m}$ Wave equation $y=0.021 \sin (x+30 t)$ Velocity of wave...

read more

5 mole of oxygen are heated at constant volume from $10^{\circ} \mathrm{C}$ to $20^{\circ} \mathrm{C} .$ What will be the change in the internal energy of gas? The molar heat of oxygen at constant pressure, $\mathrm{C}_{\mathrm{p}}=7.03 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{deg}^{-1}$ and $\mathrm{R}=8.31 \mathrm{~J} \quad$ mol $^{-1} \mathrm{deg}^{-1}$

$\mathrm{R}=8.31 \mathrm{~J} \quad \mathrm{~mol}^{-1} \mathrm{deg}^{-1}=\frac{8.31}{4.18} \mathrm{cal} \mathrm{mol}^{-1} \mathrm{deg}^{-1}$ $=1.99 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{deg}^{-1}$...

read more

A wave represented by an equation $y=a \cos (k x-\omega t) \quad$ superimposes with another wave and produces stationary wave. At $x=0$ node is formed. The equation of the second wave is
i) $y=a \sin (k x+\omega t)$
ii) $y=-a \cos (k x-\omega t)$
iii) $y=-a \sin (k x-\omega t)$
iv) $y=-a \cos (k x+\omega t)$

Correct option is D $-\mathrm{a} \cos (\mathrm{kx}+\omega \mathrm{t})$ To form a stationary wave with $y=a \cos (k x-w t)$ the wave should be in the opposite direction of this wave and amplitude...

read more

10.07 gram of silver is obtained during the circulations of electric of 5 ampere upto 30 minutes in silver nitrate pot (cell). Find out electrochemical equivalent of silver. If chemical equivalent of hydrogen is 0.00001036 then will be equivalent weight of silver

Faraday’s first law of electrolysis states that the amount of any substance deposited or liberated at any electrode is directly proportional to the quantity of electricity passed through the...

read more