A charge $\mathrm{q}$ is moving with a velocity v parallel to a magnetic field $\mathrm{B}$. Force on the charge due to magnetic field is
A quB
B $\quad q \quad B / v$
C zero
D $\mathrm{Bv} / \mathrm{q}$
A charge $\mathrm{q}$ is moving with a velocity v parallel to a magnetic field $\mathrm{B}$. Force on the charge due to magnetic field is
A quB
B $\quad q \quad B / v$
C zero
D $\mathrm{Bv} / \mathrm{q}$

Correct option is C zero
$$
\begin{array}{l}
\mathrm{F}_{\mathrm{n}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}}) \\
=\mathrm{qvB} \sin \theta \\
=0 \text { (because } \theta=0^{\circ} \text { ) }
\end{array}
$$