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The elastic energy stored per unit volume in a stretched wire is A $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}}$ B $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}}$ ,br>C $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}^{2}}$ D $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}^{2}}$
The elastic energy stored per unit volume in a stretched wire is
A $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}}$
B $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}}$ ,br>C $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}^{2}}$
D $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}^{2}}$
Physics | Previous Year Question Papers
The elastic energy stored per unit volume in a stretched wire is
A $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}}$
B $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}}$ ,br>C $\frac{1}{2} \frac{(\text { stress })^{2}}{\mathrm{Y}^{2}}$
D $\frac{1}{2} \frac{\text { (stress) }}{\mathrm{Y}^{2}}$

Correct option is
B $\frac{1(\text { stress })^{2}}{2}$
The elastic energy stored per unit volume in a stretched wire is
$$
\mathrm{u}=\frac{1}{2} \times \text { stress } \times \operatorname{strain}=\frac{(\text { stress })^{2}}{2 \mathrm{Y}}\left(\because \mathrm{Y}=\frac{\text { stress }}{\text { strain }}\right)
$$

i

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