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When current changes from $4 \mathrm{~A}$ to $0 \mathrm{~A}$ in $0.1 \mathrm{~s}$ in an inductor the induced emf is found to be $100 \mathrm{~V}$, then find the value of self-inductance is : A $0.5 \mathrm{H}$ B $2 \mathrm{H}$ C $2.5 \mathrm{H}$ D $1 \mathrm{H}$
When current changes from $4 \mathrm{~A}$ to $0 \mathrm{~A}$ in $0.1 \mathrm{~s}$ in an inductor the induced emf is found to be $100 \mathrm{~V}$, then find the value of self-inductance is :
A $0.5 \mathrm{H}$
B $2 \mathrm{H}$
C $2.5 \mathrm{H}$
D $1 \mathrm{H}$
Physics | Previous Year Question Papers
When current changes from $4 \mathrm{~A}$ to $0 \mathrm{~A}$ in $0.1 \mathrm{~s}$ in an inductor the induced emf is found to be $100 \mathrm{~V}$, then find the value of self-inductance is :
A $0.5 \mathrm{H}$
B $2 \mathrm{H}$
C $2.5 \mathrm{H}$
D $1 \mathrm{H}$

Correct option is
C $2.5 \mathrm{H}$
$$
\begin{array}{l}
\Delta \mathrm{I}=(4-0)=4 \mathrm{~A} \\
\mathrm{t}=0.1 \mathrm{~s} \\
\mathrm{e}=100 \mathrm{~V} \\
\mathrm{~L}=\frac{-\mathrm{e}}{\frac{\mathrm{dI}}{\mathrm{dt}}}=\frac{-100}{\frac{4}{01}}=-\frac{10}{4}=2.5 \mathrm{H}
\end{array}
$$

i

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